Issue 13468: Python 2.7.1 SegmentationFaults when given high recursion limit (original) (raw)

Issue13468

Created on 2011-11-24 03:49 by tdignan, last changed 2022-04-11 14:57 by admin. This issue is now closed.

Messages (2)
msg148226 - (view)	Author: Tom Dignan (tdignan)	Date: 2011-11-24 03:49
On my system, the magic number to make this segfault seems to be 26200: tom@tralfamadore ~/Downloads $ python recur1.py 26199 160164968 tom@tralfamadore ~/Downloads $ python recur1.py 26200 Segmentation fault Here's the source: #!/usr/bin/python import sys if len(sys.argv) < 2: print "usage %r " % sys.argv[0] sys.exit(1) number = int(sys.argv[1]) sys.setrecursionlimit(number + 2) f = (lambda n: (f(n - 1) if n > 0 else 0) + (n if n % 3 == 0 or n % 5 == 0 else 0)) print f(number) sys.exit(0)
msg148229 - (view)	Author: Benjamin Peterson (benjamin.peterson) *	Date: 2011-11-24 05:22
Of course; that's what the recursion limit protects against.