Issue 26148: String literals are not interned if in a tuple (original) (raw)

Issue26148

Created on 2016-01-18 20:09 by serhiy.storchaka, last changed 2022-04-11 14:58 by admin. This issue is now closed.

Messages (3)
msg258542 - (view)	Author: Serhiy Storchaka (serhiy.storchaka) *	Date: 2016-01-18 20:09
Usually string literals are interned. But not if they are a part of constant tuple. >>> def abc(): pass ... >>> x = 'abc' >>> x is abc.__name__ True >>> x = ('abc',) >>> x[0] is abc.__name__ False This makes effect on namedtuples (). May make effect on __slots__ or other uses of constant tuples since searching a value in a tuple when values are not identical is a little slower that when they are identical.
msg258594 - (view)	Author: STINNER Victor (vstinner) *	Date: 2016-01-19 13:58
FYI fatoptimizer has a more efficient algorithm to merge constants: http://fatoptimizer.readthedocs.org/en/latest/optimizations.html#comparison-with-the-peephole-optimizer It looks like it interns strings which are part of tuples. To be honest, I don't understand how it works, but it works :-)
msg277361 - (view)	Author: Serhiy Storchaka (serhiy.storchaka) *	Date: 2016-09-25 10:44
The patch is provided in .