Brownsville, Florida (original) (raw)

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Brownsville és una concentració de població designada pel cens dels Estats Units a l'estat de Florida. Segons el cens del 2000 tenia una població de 14.393 habitants.

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dbo:PopulatedPlace/areaTotal 5.9 (dbd:squareKilometre) 5.90517289156608 (dbd:squareKilometre)
dbo:abstract Brownsville és una concentració de població designada pel cens dels Estats Units a l'estat de Florida. Segons el cens del 2000 tenia una població de 14.393 habitants. (ca) Brownsville ist ein census-designated place (CDP) im Miami-Dade County im US-Bundesstaat Florida. Das U.S. Census Bureau hat bei der Volkszählung 2020 eine Einwohnerzahl von 16.583 ermittelt. (de) Brownsville (also known as Brown Sub) is a census-designated place and unincorporated community in metropolitan Miami, Florida, United States. As of the 2010 census, the population was 15,313, up from 14,393 in 2000. After three decades of population loss, Brownsville gained population for the first time in over 40 years in the 2010 US Census. (en) Brownsville es un lugar designado por el censo ubicado en el condado de Miami-Dade en el estado estadounidense de Florida. En el Censo de 2010 tenía una población de 15.313 habitantes y una densidad poblacional de 2.594,29 personas por km².​ (es) Brownsville Ameriketako Estatu Batuetako erroldak esleitutako leku bat da. Miami-Dade konderrian dago, Florida estatuan. 14.393 biztanle ditu, 5,903882 eta 5,90137 kilometro koadroko azaleran banatuta. (eu) Brownsville est une census-designated place du comté de Miami-Dade, dans l'État de Floride, aux États-Unis. En 2020, elle compte une population de 16 583 habitants. (fr) Brownsville is een plaats (census-designated place) in de Amerikaanse staat Florida, en valt bestuurlijk gezien onder Miami-Dade County. (nl) Brownsville è un Census-designated place degli Stati Uniti d'America situato nella parte settentrionale della Contea di Miami-Dade dello Stato della Florida.Secondo le stime del 2010, la città ha una popolazione di 15.313 abitanti su una superficie di 5,90 km². (it) Brownsville – jednostka osadnicza w Stanach Zjednoczonych, w stanie Floryda, w hrabstwie Miami-Dade. (pl) Браунсвилл (англ. Brownsville) — статистически обособленная местность, расположенная в округе Майами-Дейд (штат Флорида, США) с населением в 14 393 человека по статистическим данным переписи 2000 года. (ru) Brownsville är en ort (CDP) i Miami-Dade County, i delstaten Florida, USA. Enligt United States Census Bureau har orten en folkmängd på 15 313 invånare (2010) och en landarea på 5,9 km². (sv) Brownsville é uma Região censo-designada localizada no estado americano da Flórida, no Condado de Miami-Dade. (pt) Браунсвілл (англ. Brownsville) — переписна місцевість (CDP) в США, в окрузі Маямі-Дейд штату Флорида. Населення — 15 313 осіб (2010). (uk) 布朗斯維爾(英語:Brownsville)是位於美國佛羅里達州艾斯康比亞縣的一個非建制地區。該地的面積和人口皆未知。 (zh)
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dbp:inline box (en)
dbp:line Green (en) Silver Star (en) Tri (en)
dbp:mapCaption U.S. Census Bureau map showing CDP boundaries (en) Location in Miami-Dade County and the state of Florida (en)
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dbp:officialName Brownsville (en)
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rdfs:comment Brownsville és una concentració de població designada pel cens dels Estats Units a l'estat de Florida. Segons el cens del 2000 tenia una població de 14.393 habitants. (ca) Brownsville ist ein census-designated place (CDP) im Miami-Dade County im US-Bundesstaat Florida. Das U.S. Census Bureau hat bei der Volkszählung 2020 eine Einwohnerzahl von 16.583 ermittelt. (de) Brownsville (also known as Brown Sub) is a census-designated place and unincorporated community in metropolitan Miami, Florida, United States. As of the 2010 census, the population was 15,313, up from 14,393 in 2000. After three decades of population loss, Brownsville gained population for the first time in over 40 years in the 2010 US Census. (en) Brownsville es un lugar designado por el censo ubicado en el condado de Miami-Dade en el estado estadounidense de Florida. En el Censo de 2010 tenía una población de 15.313 habitantes y una densidad poblacional de 2.594,29 personas por km².​ (es) Brownsville Ameriketako Estatu Batuetako erroldak esleitutako leku bat da. Miami-Dade konderrian dago, Florida estatuan. 14.393 biztanle ditu, 5,903882 eta 5,90137 kilometro koadroko azaleran banatuta. (eu) Brownsville est une census-designated place du comté de Miami-Dade, dans l'État de Floride, aux États-Unis. En 2020, elle compte une population de 16 583 habitants. (fr) Brownsville is een plaats (census-designated place) in de Amerikaanse staat Florida, en valt bestuurlijk gezien onder Miami-Dade County. (nl) Brownsville è un Census-designated place degli Stati Uniti d'America situato nella parte settentrionale della Contea di Miami-Dade dello Stato della Florida.Secondo le stime del 2010, la città ha una popolazione di 15.313 abitanti su una superficie di 5,90 km². (it) Brownsville – jednostka osadnicza w Stanach Zjednoczonych, w stanie Floryda, w hrabstwie Miami-Dade. (pl) Браунсвилл (англ. Brownsville) — статистически обособленная местность, расположенная в округе Майами-Дейд (штат Флорида, США) с населением в 14 393 человека по статистическим данным переписи 2000 года. (ru) Brownsville är en ort (CDP) i Miami-Dade County, i delstaten Florida, USA. Enligt United States Census Bureau har orten en folkmängd på 15 313 invånare (2010) och en landarea på 5,9 km². (sv) Brownsville é uma Região censo-designada localizada no estado americano da Flórida, no Condado de Miami-Dade. (pt) Браунсвілл (англ. Brownsville) — переписна місцевість (CDP) в США, в окрузі Маямі-Дейд штату Флорида. Населення — 15 313 осіб (2010). (uk) 布朗斯維爾(英語:Brownsville)是位於美國佛羅里達州艾斯康比亞縣的一個非建制地區。該地的面積和人口皆未知。 (zh)
rdfs:label Brownsville, Florida (en) Brownsville (Florida) (ca) Brownsville (Florida) (de) Brownsville (Florida) (es) Brownsville (Florida) (eu) Brownsville (Floride) (fr) Brownsville (Florida) (it) Brownsville (Florida) (nl) Brownsville (Floryda) (pl) Brownsville (Flórida) (pt) Браунсвилл (Флорида) (ru) Brownsville, Florida (sv) 布朗斯維爾 (佛羅里達州艾斯康比亞縣) (zh) Браунсвілл (Флорида) (uk)
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