Derbin Island (original) (raw)
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Island in Alaska, United States
Derbin
  DerbinDerbin Island in the U.S. state of Alaska. |
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|---|---|
| Geography | |
| Location | Northern Pacific Ocean |
| Coordinates | 54°04′16″N 165°09′12″W / 54.07111°N 165.15333°W / 54.07111; -165.15333 |
| Archipelago | Aleutian Islands |
| Length | 0.840 km (0.522 mi) |
| Highest elevation | 10 ft (3 m) |
| Administration | |
| United States | |
| State | Alaska |
| Borough | Fox Islands |
| Demographics | |
| Population | Uninhabited |
Derbin Island is located in the Krenitzin Islands, a subgroup of the Fox Islands in the eastern Aleutian Islands, Alaska, United States.[1] Derbin is a small island (at 0.5 mi across) and is situated near the southwestern shore of Tigalda Island. It is measuring 840 metres (0.52 mi) long and 204 metres (0.127 mi) wide. It was named in 1935 by the United States Coast and Geodetic Survey because of its proximity to Derbin Strait, the channel between Avatanak and Tigalda islands. Derbin Strait, in turn, is derived from "Derbenskoy," the Russian name published by Father Veniaminov (1840).[2]
- ^ "Feature Detail Report for: Derbin Island". Geographic Names Information System. United States Geological Survey, United States Department of the Interior.
- ^ "Feature Detail Report for: Derbin Strait". Geographic Names Information System. United States Geological Survey.
54°04′16″N 165°09′12″W / 54.07111°N 165.15333°W / 54.07111; -165.15333