Sort-merge join (original) (raw)

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Algorithm used in relational databases

The sort-merge join (also known as merge join) is a join algorithm and is used in the implementation of a relational database management system.

The basic problem of a join algorithm is to find, for each distinct value of the join attribute, the set of tuples in each relation which display that value. The key idea of the sort-merge algorithm is to first sort the relations by the join attribute, so that interleaved linear scans will encounter these sets at the same time.

In practice, the most expensive part of performing a sort-merge join is arranging for both inputs to the algorithm to be presented in sorted order. This can be achieved via an explicit sort operation (often an external sort), or by taking advantage of a pre-existing ordering in one or both of the join relations.[1] The latter condition, called interesting order, can occur because an input to the join might be produced by an index scan of a tree-based index, another merge join, or some other plan operator that happens to produce output sorted on an appropriate key. Interesting orders need not be serendipitous: the optimizer may seek out this possibility and choose a plan that is suboptimal for a specific preceding operation if it yields an interesting order that one or more downstream nodes can exploit.

Let R {\displaystyle R} $R$ and S {\displaystyle S} $S$ be relations where | R | < | S | {\displaystyle |R|<|S|} $|R|<|S|$ . R {\displaystyle R} $R$ fits in P r {\displaystyle P_{r}} $P_{r}$ pages memory and S {\displaystyle S} $S$ fits in P s {\displaystyle P_{s}} $P_{s}$ pages memory. In the worst case, a sort-merge join will run in O ( P r + P s ) {\displaystyle O(P_{r}+P_{s})} $O(P_{r}+P_{s})$ I/O operations. In the case that R {\displaystyle R} $R$ and S {\displaystyle S} $S$ are not ordered the worst case time cost will contain additional terms of sorting time: O ( P r + P s + P r log ⁡ ( P r ) + P s log ⁡ ( P s ) ) {\displaystyle O(P_{r}+P_{s}+P_{r}\log(P_{r})+P_{s}\log(P_{s}))} $O(P_{r}+P_{s}+P_{r}\log(P_{r})+P_{s}\log(P_{s}))$ , which equals O ( P r log ⁡ ( P r ) + P s log ⁡ ( P s ) ) {\displaystyle O(P_{r}\log(P_{r})+P_{s}\log(P_{s}))} $O(P_{r}\log(P_{r})+P_{s}\log(P_{s}))$ (as linearithmic terms outweigh the linear terms, see Big O notation – Orders of common functions).

For simplicity, the algorithm is described in the case of an inner join of two relations left and right. Generalization to other join types is straightforward. The output of the algorithm will contain only rows contained in the left and right relation and duplicates form a Cartesian product.

function Sort-Merge Join(left: Relation, right: Relation, comparator: Comparator) { result = new Relation()

// Ensure that at least one element is present
if (!left.hasNext() || !right.hasNext()) {
    return result
}

// Sort left and right relation with comparator
left.sort(comparator)
right.sort(comparator)

// Start Merge Join algorithm
leftRow = left.next()
rightRow = right.next()

outerForeverLoop:
while (true) {
    while (comparator.compare(leftRow, rightRow) != 0) {
        if (comparator.compare(leftRow, rightRow) < 0) {
            // Left row is less than right row
            if (left.hasNext()) {
                // Advance to next left row
                leftRow = left.next()
            } else {
                break outerForeverLoop
            }
        } else {
            // Left row is greater than right row
            if (right.hasNext()) {
                // Advance to next right row
                rightRow  = right.next()
            } else {
                break outerForeverLoop
            }
        }
    }
    
    // Mark position of left row and keep copy of current left row
    left.mark()
    markedLeftRow = leftRow
    
    while (true) {
        while (comparator.compare(leftRow, rightRow) == 0) {
            // Left row and right row are equal
            // Add rows to result
            result = add(leftRow, rightRow)
            
            // Advance to next left row
            leftRow = left.next()
            
            // Check if left row exists
            if (!leftRow) {
                // Continue with inner forever loop
                break
            }
        }
        
        if (right.hasNext()) {
            // Advance to next right row
            rightRow  = right.next()
        } else {
            break outerForeverLoop
        }
        
        if (comparator.compare(markedLeftRow, rightRow) == 0) {
            // Restore left to stored mark
            left.restoreMark()
            leftRow = markedLeftRow
        } else {
            // Check if left row exists
            if (!leftRow) {
                break outerForeverLoop
            } else {
                // Continue with outer forever loop
                break
            }
        }
    }
}

return result

}

Since the comparison logic is not the central aspect of this algorithm, it is hidden behind a generic comparator and can also consist of several comparison criteria (e.g. multiple columns). The compare function should return if a row is less(-1), equal(0) or bigger(1) than another row:

function compare(leftRow: RelationRow, rightRow: RelationRow): number { // Return -1 if leftRow is less than rightRow // Return 0 if leftRow is equal to rightRow // Return 1 if leftRow is greater than rightRow }

Note that a relation in terms of this pseudocode supports some basic operations:

interface Relation { // Returns true if relation has a next row (otherwise false) hasNext(): boolean

// Returns the next row of the relation (if any)
next(): RelationRow

// Sorts the relation with the given comparator
sort(comparator: Comparator): void

// Marks the current row index
mark(): void

// Restores the current row index to the marked row index
restoreMark(): void

}

Simple C# implementation

[edit]

Note that this implementation assumes the join attributes are unique, i.e., there is no need to output multiple tuples for a given value of the key.

public class MergeJoin { // Assume that left and right are already sorted public static Relation Merge(Relation left, Relation right) { Relation output = new Relation(); while (!left.IsPastEnd && !right.IsPastEnd) { if (left.Key == right.Key) { output.Add(left.Key); left.Advance(); right.Advance(); } else if (left.Key < right.Key) left.Advance(); else // if (left.Key > right.Key) right.Advance(); } return output; } }

public class Relation { private List list; public const int ENDPOS = -1;

public int position = 0;
public int Position => position;

public int Key => list[position];

public bool IsPastEnd => position == ENDPOS;

public bool Advance()
{
    if (position == list.Count - 1 || position == ENDPOS)
    {
        position = ENDPOS;
        return false;
    }
    position++;
    return true;
}

public void Add(int key)
{
    list.Add(key);
}

public void Print()
{
    foreach (int key in list)
        Console.WriteLine(key);
}

public Relation(List<int> list)
{
    this.list = list;
}

public Relation()
{
    this.list = new List<int>();
}

}

^ "Sort-Merge Joins". www.dcs.ed.ac.uk. Retrieved 2022-11-02.

C# Implementations of Various Join Algorithms