cpython: c39457a07caa (original) (raw)

Mercurial > cpython

changeset 91990:c39457a07caa 3.4

#18588: update the timeit examples to be consistent. [#18588]

Ezio Melotti ezio.melotti@gmail.com
date	Mon, 04 Aug 2014 17:01:16 +0300
parents	a42f14ff0f9a
children	45b208ae9eab 9ec2b429a607
files	Doc/library/timeit.rst
diffstat	1 files changed, 10 insertions(+), 9 deletions(-)[+] [-] Doc/library/timeit.rst 19

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--- a/Doc/library/timeit.rst +++ b/Doc/library/timeit.rst @@ -28,22 +28,23 @@ can be used to compare three different e .. code-block:: sh

$ python -m timeit '"-".join(str(n) for n in range(100))'
10000 loops, best of 3: 40.3 usec per loop
$ python -m timeit '"-".join([str(n) for n in range(100)])'
10000 loops, best of 3: 33.4 usec per loop
$ python -m timeit '"-".join(map(str, range(100)))'
10000 loops, best of 3: 25.2 usec per loop

$ python3 -m timeit '"-".join(str(n) for n in range(100))'
10000 loops, best of 3: 30.2 usec per loop
$ python3 -m timeit '"-".join([str(n) for n in range(100)])'
10000 loops, best of 3: 27.5 usec per loop
$ python3 -m timeit '"-".join(map(str, range(100)))'
10000 loops, best of 3: 23.2 usec per loop

This can be achieved from the :ref:python-interface with:: >>> import timeit >>> timeit.timeit('"-".join(str(n) for n in range(100))', number=10000)

0.8187260627746582

0.3018611848820001

timeit.timeit('"-".join([str(n) for n in range(100)])', number=10000)

0.7288308143615723

0.2727368790656328

timeit.timeit('"-".join(map(str, range(100)))', number=10000)

0.5858950614929199

0.23702679807320237 +

Note however that :mod:timeit will automatically determine the number of repetitions only when the command-line interface is used. In the