socket.getservbyname(servicename[, protocolname])
->
socket.getservbyname(servicename, protocolname=None)

Here is a more complicated example, since the above does technically have an alternative fix:
">

(original) (raw)

On Wed, Jan 15, 2014 at 7:57 PM, Ryan Smith-Roberts <rmsr@lab.net> wrote:
socket.getservbyname(servicename\[, protocolname\])
->
socket.getservbyname(servicename, protocolname=None)

Here is a more complicated example, since the above does technically have an alternative fix:


sockobj.sendmsg(buffers[, ancdata[, flags[, address]]])
->
sockobj.sendmsg(buffers, ancdata=None, flags=0, address=None)