(original) (raw)
\[\zeta'\left(1-2n,\tfrac{1}{2}\right)=-\frac{B_{2n}\ln 2}{n\cdot 4^{n}}-\frac{(% 2^{2n-1}-1)\zeta'\left(1-2n\right)}{2^{2n-1}},\]
\[\zeta'\left(1-2n,\tfrac{1}{2}\right)=-\frac{B_{2n}\ln 2}{n\cdot 4^{n}}-\frac{(% 2^{2n-1}-1)\zeta'\left(1-2n\right)}{2^{2n-1}},\]