numpy.linalg.pinv — NumPy v1.11 Manual (original) (raw)

numpy.linalg.pinv(a, rcond=1e-15)[source]

Compute the (Moore-Penrose) pseudo-inverse of a matrix.

Calculate the generalized inverse of a matrix using its singular-value decomposition (SVD) and including all_large_ singular values.

Parameters: a : (M, N) array_like Matrix to be pseudo-inverted. rcond : float Cutoff for small singular values. Singular values smaller (in modulus) than_rcond_ * largest_singular_value (again, in modulus) are set to zero.
Returns: B : (N, M) ndarray The pseudo-inverse of a. If a is a matrix instance, then so is B.
Raises: LinAlgError If the SVD computation does not converge.

Notes

The pseudo-inverse of a matrix A, denoted A^+, is defined as: “the matrix that ‘solves’ [the least-squares problem]Ax = b,” i.e., if \bar{x} is said solution, thenA^+ is that matrix such that \bar{x} = A^+b.

It can be shown that if Q_1 \Sigma Q_2^T = A is the singular value decomposition of A, thenA^+ = Q_2 \Sigma^+ Q_1^T, where Q_{1,2} are orthogonal matrices, \Sigma is a diagonal matrix consisting of A’s so-called singular values, (followed, typically, by zeros), and then \Sigma^+ is simply the diagonal matrix consisting of the reciprocals of A’s singular values (again, followed by zeros). [R42]

References

[R42] (1, 2) G. Strang, Linear Algebra and Its Applications, 2nd Ed., Orlando, FL, Academic Press, Inc., 1980, pp. 139-142.

Examples

The following example checks that a * a+ * a == a anda+ * a * a+ == a+:

a = np.random.randn(9, 6) B = np.linalg.pinv(a) np.allclose(a, np.dot(a, np.dot(B, a))) True np.allclose(B, np.dot(B, np.dot(a, B))) True