numpy.setdiff1d — NumPy v1.11 Manual (original) (raw)
numpy.setdiff1d(ar1, ar2, assume_unique=False)[source]¶
Find the set difference of two arrays.
Return the sorted, unique values in ar1 that are not in ar2.
Parameters: | ar1 : array_like Input array. ar2 : array_like Input comparison array. assume_unique : bool If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False. |
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Returns: | setdiff1d : ndarray Sorted 1D array of values in ar1 that are not in ar2. |
See also
numpy.lib.arraysetops
Module with a number of other functions for performing set operations on arrays.
Examples
a = np.array([1, 2, 3, 2, 4, 1]) b = np.array([3, 4, 5, 6]) np.setdiff1d(a, b) array([1, 2])