std::array<T,N>::operator[] - cppreference.com (original) (raw)

reference operator[]( size_type pos ); (1) (since C++11) (constexpr since C++17)
const_reference operator[]( size_type pos ) const; (2) (since C++11) (constexpr since C++14)

Returns a reference to the element at specified location pos.

If pos < size() is false, the behavior is undefined. (until C++26)
If pos < size() is false: If the implementation is hardened, a contract violation occurs. Moreover, if the contract-violation handler returns under “observe” evaluation semantic, the behavior is undefined. If the implementation is not hardened, the behavior is undefined. (since C++26)

[edit] Parameters

pos - position of the element to return

[edit] Return value

Reference to the requested element.

[edit] Complexity

Constant.

[edit] Notes

Unlike std::map::operator[], this operator never inserts a new element into the container. Accessing a nonexistent element through this operator is undefined behavior, unless the implementation is hardened(since C++26).

[edit] Example

The following code uses operator[] to read from and write to a std::array<int, N>:

#include #include   int main() { std::array<int, 4> numbers{2, 4, 6, 8};   std::cout << "Second element: " << numbers[1] << '\n';   numbers[0] = 5;   std::cout << "All numbers:"; for (auto i : numbers) std::cout << ' ' << i; std::cout << '\n'; }

Output:

Second element: 4 All numbers: 5 4 6 8

[edit] See also

| | access specified element with bounds checking (public member function) [edit] | | ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |