std::filesystem::operator/(std::filesystem::path) - cppreference.com (original) (raw)

| friend path operator/( const path& lhs, const path& rhs ); | | (since C++17) | | ---------------------------------------------------------- | | ------------- |

Concatenates two path components using the preferred directory separator if appropriate (see operator/= for details).

Effectively returns path(lhs) /= rhs.

This function is not visible to ordinary unqualified or qualified lookup, and can only be found by argument-dependent lookup when std::filesystem::path is an associated class of the arguments. This prevents undesirable conversions in the presence of a using namespace std::filesystem; using-directive.

[edit] Parameters

[edit] Return value

The result of path concatenation.

[edit] Example

#include #include   int main() {

if defined(_WIN32) // see e.g. stackoverflow.com/questions/142508

  std::filesystem::path p = "C:";   std::cout << R"("C:" / "Users" / "batman" == )" << p / "Users" / "batman" << '\n';  

else // linux etc

  std::filesystem::path p = "/home";   std::cout << R"("/home" / "tux" / ".fonts" ==)" << p / "tux" / ".fonts" << '\n';  

endif

}

Possible output:

Windows specific output: "C:" / "Users" / "batman" == "C:Users\batman"   Linux etc specific output: "/home" / "tux" / ".fonts" == "/home/tux/.fonts"

[edit] Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

[edit] See also