std::indirect_result_t - cppreference.com (original) (raw)

The alias template indirect_result_t obtains the result type of invoking an invocable type F on the result of dereferencing indirectly_readable types Is....

[edit] Template parameters

F - an invocable type
Is - indirectly readable types that are dereferenced to arguments

[edit] Example

#include #include   struct Fn { long operator()(const int&); int operator()(int&&); short operator()(int, int) const; auto operator()(const float) -> int&; void operator()(int[8]); };   static_assert( std::is_same_v<std::indirect_result_t<Fn, const int*>, long> and std::is_same_v<std::indirect_result_t<Fn, std::move_iterator<int*>>, int> and std::is_same_v<std::indirect_result_t<const Fn, int*, int*>, short> and std::is_same_v<std::indirect_result_t<Fn, float*>, int&> and std::is_same_v<std::indirect_result_t<Fn, int**>, void> );   int main() {}

[edit] See also