std::abs, std::labs, std::llabs, std::imaxabs - cppreference.com (original) (raw)

Defined in header
Defined in header
int abs( int num ); (1) (constexpr since C++23)
long abs( long num ); (2) (constexpr since C++23)
long long abs( long long num ); (3) (since C++11) (constexpr since C++23)
Defined in header
long labs( long num ); (4) (constexpr since C++23)
long long llabs( long long num ); (5) (since C++11) (constexpr since C++23)
Defined in header
std::intmax_t abs( std::intmax_t num ); (6) (since C++11) (constexpr since C++23)
std::intmax_t imaxabs( std::intmax_t num ); (7) (since C++11) (constexpr since C++23)

Computes the absolute value of the integer number num. The behavior is undefined if the result cannot be represented by the return type.

If std::abs is called with an unsigned integral argument that cannot be converted to int by integral promotion, the program is ill-formed.

[edit] Parameters

[edit] Return value

The absolute value of num (i.e. |num|), if it is representable.

[edit] Notes

In 2's complement systems, the absolute value of the most-negative value is out of range, e.g. for 32-bit 2's complement type int, INT_MIN is -2147483648, but the would-be result 2147483648 is greater than INT_MAX, which is 2147483647.

[edit] Example

#include #include #include   int main() { std::cout << std::showpos << "abs(+3) = " << std::abs(3) << '\n' << "abs(-3) = " << std::abs(-3) << '\n';   // std::cout << std::abs(INT_MIN); // undefined behavior on 2's complement systems }

Output:

abs(+3) = +3 abs(-3) = +3

[edit] Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR Applied to Behavior as published Correct behavior
LWG 2192 C++98 overloads of std::abs wereinconsistently declared in two headers declared these overloadsin both headers

[edit] See also