std::make_pair - cppreference.com (original) (raw)
| Defined in header | | | | ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ | | --------------------------------------------------- | | template< class T1, class T2 > std::pair<T1, T2> make_pair( T1 x, T2 y ); | | (until C++11) | | template< class T1, class T2 > std::pair</*V1*/, /*V2*/> make_pair( T1&& x, T2&& y ); | | (since C++11) (constexpr since C++14) (until C++20) | | template< class T1, class T2 > constexpr std::pair<std::unwrap_ref_decay_t<T1>, std::unwrap_ref_decay_t<T2>> make_pair( T1&& x, T2&& y ); | | (since C++20) |
Creates a std::pair object, deducing the target type from the types of arguments.
[edit] Parameters
x, y | - | the values to construct the pair from |
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[edit] Return value
[edit] Example
#include #include #include int main() { int n = 1; int a[5] = {1, 2, 3, 4, 5}; // build a pair from two ints auto p1 = std::make_pair(n, a[1]); std::cout << "The value of p1 is " << '(' << p1.first << ", " << p1.second << ")\n"; // build a pair from a reference to int and an array (decayed to pointer) auto p2 = std::make_pair(std::ref(n), a); n = 7; std::cout << "The value of p2 is " << '(' << p2.first << ", " << *(p2.second + 2) << ")\n"; }
Output:
The value of p1 is (1, 2) The value of p2 is (7, 3)
[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
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LWG 181 | C++98 | the parameter types were const-referencetypes, which made passing arrays impossible | changed thesetypes to value types |