Map.asFunction (original) (raw)

Remi Forax forax at univ-mlv.fr
Fri Jan 4 09:17:04 PST 2013

On 01/04/2013 04:29 PM, Brian Goetz wrote:

We didn't decide not to. (Similarly Set.asPredicate()) No objection (the body can be this::get). No objection.

On 1/4/2013 10:17 AM, Doug Lea wrote:

There is no Map interface method: default Function<K,V> asFunction() { return { k -> get(k) }; } Did we decide not to do this or just forget to do it? -Doug

Not sure it worth a method as it can be written map::get or set::contains.

Rémi

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