[Python-checkins] r54811 - in sandbox/trunk/2to3: pytree.py tests/test_pytree.py (original) (raw)
collin.winter python-checkins at python.org
Sat Apr 14 00:05:53 CEST 2007
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Author: collin.winter Date: Sat Apr 14 00:05:51 2007 New Revision: 54811
Modified: sandbox/trunk/2to3/pytree.py sandbox/trunk/2to3/tests/test_pytree.py Log: Add a get_suffix() method to pytree.Base.
Modified: sandbox/trunk/2to3/pytree.py
--- sandbox/trunk/2to3/pytree.py (original) +++ sandbox/trunk/2to3/pytree.py Sat Apr 14 00:05:51 2007 @@ -142,7 +142,7 @@ del self.parent.children[i] self.parent = None return i
def get_next_sibling(self): """Return the node immediately following the invocant in their parent's children list. If the invocant does not have a next
@@ -157,6 +157,14 @@ return self.parent.children[i+1] except IndexError: return None
- def get_suffix(self):
"""Return the string immediately following the invocant node. This
is effectively equivalent to node.get_next_sibling().get_prefix()"""
next_sib = self.get_next_sibling()
if next_sib is None:
return ""
return next_sib.get_prefix()
class Node(Base):
Modified: sandbox/trunk/2to3/tests/test_pytree.py
--- sandbox/trunk/2to3/tests/test_pytree.py (original) +++ sandbox/trunk/2to3/tests/test_pytree.py Sat Apr 14 00:05:51 2007 @@ -99,6 +99,22 @@ self.assertEqual(n1.get_prefix(), " ") self.assertEqual(l1.get_prefix(), " ")
- def testGetSuffix(self):
l1 = pytree.Leaf(100, "foo", prefix="a")
l2 = pytree.Leaf(100, "bar", prefix="b")
n1 = pytree.Node(1000, [l1, l2])
self.assertEqual(l1.get_suffix(), l2.get_prefix())
self.assertEqual(l2.get_suffix(), "")
self.assertEqual(n1.get_suffix(), "")
l3 = pytree.Leaf(100, "bar", prefix="c")
n2 = pytree.Node(1000, [n1, l3])
self.assertEqual(n1.get_suffix(), l3.get_prefix())
self.assertEqual(l3.get_suffix(), "")
self.assertEqual(n2.get_suffix(), "")
def testNodeEq(self): n1 = pytree.Node(1000, ()) n2 = pytree.Node(1000, [], context=(" ", (1, 0)))
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