[Python-Dev] Go \x yourself (original) (raw)

Ka-Ping Yee ping@lfw.org
Fri, 4 Aug 2000 01:38:12 -0700 (PDT)

On Thu, 3 Aug 2000, Tim Peters wrote:

>>> "\x123465" # \x12 -> \022, "3456" left alone '\0223456' >>> "\x65" 'e' >>> "\x1" ValueError >>> "\x\x" ValueError >>>

I'm quite certain that this should be a SyntaxError, not a ValueError:

>>> "\x1"
SyntaxError: two hex digits are required after \x
>>> "\x\x"
SyntaxError: two hex digits are required after \x

Otherwise, +1. Sounds great.

-- ?!ng