[Python-Dev] FW: if-else with '|' operator (original) (raw)

[Python-Dev] FW: if-else with '|' operator - beginner's question/problem

Tim Peters tim.one@home.com
Wed, 8 Aug 2001 14:13:56 -0400

What a fascinating newbie confusion! It surprised and tickled me.

FYI, in Icon this kind of thing "just works". e1 | e2 | ... | en is "a generator" there too, and acts like the Python

def g(): for x in e1: yield x for x in e2: yield x ... for x in en: yield en

Then the expression y1 == y2 generates the cross-product of the y1 and y2 sequences, succeeding in the end iff some pair of generated values compares equal.

No, I'm not suggesting Python do that too . It's more in the way of noting that no matter how odd a question looks to you, some peoples' brains are so wired that it's hard for them to view it otherwise.

finally-understanding-vi-users-ly y'rs - tim

-----Original Message----- From: python-list-admin@python.org Sent: Wednesday, August 08, 2001 1:26 PM To: python-list@python.org Subject: if-else with '|' operator - beginner's question/problem

Hi there, I wonder if someone could possibly tell me what is wrong with the following statement. I'm extremely embarrased to ask but here goes...

if (fname[1] == 'a'|'e'|'i'|'o'|'u'): vowel='true'

Traceback (innermost last): File "<pyshell#46>", line 1, in ? if (fname[1] == 'a'|'e'|'i'|'o'|'u'): TypeError: bad operand type(s) for |

fname[1] gives 'e'

Thanks very much in advance!

Lee

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