[Python-Dev] Change to PyIter_Next()? (original) (raw)
Tim Peters tim.one@home.com
Fri, 4 May 2001 16:50:03 -0400
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In spare moments, I've been plugging away at making various functions work nice with iterators (map, min, max, etc).
Over and over this requires writing code of the form:
op2 = PyIter_Next(it);
if (op2 == NULL) {
/* StopIteration is *implied* by a NULL return from
* PyIter_Next() if PyErr_Occurred() is false.
*/
if (PyErr_Occurred()) {
if (PyErr_ExceptionMatches(PyExc_StopIteration))
PyErr_Clear();
else
goto Fail;
}
break;
}
This is wordy, obscure, and in my experience is needed every time I call PyIter_Next().
So I'd like to hide this in PyIter_Next instead, like so:
/* Return next item.
- If an error occurs, return NULL and set *error=1.
- If the iteration terminated normally, return NULL and set *error=0.
- Else return the next object and set *error=0. */ PyObject * PyIter_Next(PyObject *iter, int *error) { PyObject *result; if (!PyIter_Check(iter)) { PyErr_Format(PyExc_TypeError, "'%.100s' object is not an iterator", iter->ob_type->tp_name); *error = 1; return NULL; } result = (*iter->ob_type->tp_iternext)(iter); *error = 0; if (result) return result; if (PyErr_Occurred()) { if (PyErr_ExceptionMatches(PyExc_StopIteration)) PyErr_Clear(); else error = 1; } / Else StopIteration is implicit, and there is no error. */ return NULL; }
Then calls could be the simpler:
op2 = PyIter_Next(it, &error);
if (op2 == NULL) {
if {error)
goto Fail;
break;
}
Objections? So far I'm almost the only user of PyIter_Next(); the only other use is in ceval's FOR_ITER, which goes thru a similar dance.
However, I'm not clear on why FOR_ITER doesn't clear the exception if PyErr_Occurred() and PyErr_ExceptionMatches(PyExc_StopIteration) are both true -- that sure smells like a bug (but, if so, the change above would squash it by magic).
Note that I'm not proposing to change the signature of the tp_iternext slot similarly. PyIter_Next() is a (IMO appropriately) higher-level function.
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