[Python-Dev] traceback.py still broken in 2.5a2 (original) (raw)
Guido van Rossum guido at python.org
Thu Apr 27 20:38:48 CEST 2006
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The change below was rolled back because it broke other stuff. But IMO it is actually necessary to fix this, otherwise those few exceptions that don't derive from Exception won't be printed correctly by the traceback module:
guido:~/p/osx guido$ ./python.exe Python 2.5a2 (trunk:45765, Apr 27 2006, 11:36:10) [GCC 4.0.0 20041026 (Apple Computer, Inc. build 4061)] on darwin Type "help", "copyright", "credits" or "license" for more information.
def f(): ... raise KeyboardInterrupt ... f() Traceback (most recent call last): File "", line 1, in File "", line 2, in f KeyboardInterrupt import traceback try: ... f() ... except: ... traceback.print_exc() ... Traceback (most recent call last): File "", line 2, in File "", line 2, in f <class 'exceptions.KeyboardInterrupt'>
--Guido
---------- Forwarded message ---------- From: phillip.eby <python-checkins at python.org> Date: Mar 24, 2006 3:10 PM Subject: [Python-checkins] r43299 - python/trunk/Lib/traceback.py To: python-checkins at python.org
Author: phillip.eby Date: Fri Mar 24 23:10:54 2006 New Revision: 43299
Modified: python/trunk/Lib/traceback.py Log: Revert r42719, because the isinstance() check wasn't redundant; formatting a string exception was causing a TypeError.
Modified: python/trunk/Lib/traceback.py
--- python/trunk/Lib/traceback.py (original) +++ python/trunk/Lib/traceback.py Fri Mar 24 23:10:54 2006 @@ -158,7 +158,7 @@ """ list = [] if (type(etype) == types.ClassType
or issubclass(etype, Exception)):
else: stype = etypeor (isinstance(etype, type) and issubclass(etype, Exception))): stype = etype.__name__
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-- --Guido van Rossum (home page: http://www.python.org/~guido/)
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