[Python-Dev] Are PyCFunctions supposed to invisibly consume self when used as a method? (original) (raw)

Guido van Rossum guido at python.org
Sun Jun 13 01:16:17 CEST 2010

(Of course, I'd still like to see the warning, since it's now a portability issue.)

On Sat, Jun 12, 2010 at 4:15 PM, Guido van Rossum <guido at python.org> wrote:

Hey! No borrowing the time machine! :-)

On Sat, Jun 12, 2010 at 4:03 PM, Christian Heimes <lists at cheimes.de> wrote:

method or instancemethod perhaps?

The necessary code is already in Python 3.0's code base. I've added in in r56469 as requested in my issue http://bugs.python.org/issue1587. It seems we had this very discussion over two and a half year ago. Index: Python/bltinmodule.c =================================================================== --- Python/bltinmodule.c        (Revision 81963) +++ Python/bltinmodule.c        (Arbeitskopie) @@ -2351,6 +2351,7 @@ SETBUILTIN("frozenset",             &PyFrozenSetType); SETBUILTIN("property",              &PyPropertyType); SETBUILTIN("int",                   &PyLongType); +    SETBUILTIN("instancemethod",        &PyInstanceMethodType); SETBUILTIN("list",                  &PyListType); SETBUILTIN("map",                   &PyMapType); SETBUILTIN("object",                &PyBaseObjectType);

class Example: ...     iid = instancemethod(id) ...     id = id ... Example().id() Traceback (most recent call last):  File "", line 1, in TypeError: id() takes exactly one argument (0 given) Example().iid() 139941157882144 Christian

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-- --Guido van Rossum (python.org/~guido)

-- --Guido van Rossum (python.org/~guido)

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