[Python-Dev] Strange message error in socket.sendto() exception (original) (raw)
Facundo Batista facundobatista at gmail.com
Sat Aug 20 12:58:13 CEST 2011
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Python 3.2 (r32:88445, Mar 25 2011, 19:28:28) [GCC 4.5.2] on linux2
import socket s = socket.socket() print(s.sendto.doc) sendto(data[, flags], address) -> count ... s.sendto(b'data', ('localhost', 3)) Traceback (most recent call last): File "", line 1, in socket.error: [Errno 32] Broken pipe
This is ok, I expected this. However, note what happens if I send unicode:
s.sendto('data', ('localhost', 3)) Traceback (most recent call last): File "", line 1, in TypeError: sendto() takes exactly 3 arguments (2 given)
An error regarding the argument quantity? what?
Furthermore, where this message comes from? I tried to find, but the only hint I get is that it could come from "./Modules/_ctypes/_ctypes.c"... are we using ctypes to access socket methods? it's strange, because "sendto" is defined in socketmodule.c.
Ideas? Thanks!
-- . Facundo
Blog: http://www.taniquetil.com.ar/plog/ PyAr: http://www.python.org/ar/
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