[Python-ideas] Pythonic Dates, Times, and Deltas (original) (raw)

Daniel G. Taylor danielgtaylor at gmail.com
Thu Oct 14 20:51:05 CEST 2010

On 10/14/2010 08:06 AM, Masklinn wrote:

On 2010-10-14, at 10:02 , Marco Mariani wrote:

On 13 October 2010 23:17, Alexander Belopolsky<_ _alexander.belopolsky at gmail.com> wrote: * Make it easy to get a tuple of the start and end of the month

Why would you want this? Start of the month is easy: just date(year, month, 1). End of the month is often unnecessary because it is more pythonic to work with semi-open ranges and use first of the next month instead. Except next month may well be in next year.. blah And I don't care about pythonic ranges if I have to push the values through a BETWEEN query in SQL. import calendar import datetime end = datetime.date(year, month, calendar.monthrange(year, month)[1]) There's also dateutil, which exposes some ideas of mx.DateTime on top of the built-in datetime, including relativedelta. As a result, you can get the last day of the current month by going backwards one day from the first day of next month: datetime.now().date() + relativedelta(months=+1, day=+1, days=-1) datetime.date(2010, 10, 31) Or (clearer order of operations): datetime.now().date() + relativedelta(months=+1, day=+1) + relativedelta(days=-1) datetime.date(2010, 10, 31) (note that in both cases the "+" sign is of course optional). Parameters without an s postfix are absolute (day=1 sets the day of the current datetime to 1, similar to using .replace), parameters with an s are offsets (days=+1 takes tomorrow).

FWIW my library does the same sort of stuff using relativedelta internally, just sugar coats it heavily ;-)

Take care,

Daniel G. Taylor http://programmer-art.org/

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