[Tutor] Is there a better way to do this? (original) (raw)
Alan Gauld alan.gauld at blueyonder.co.uk
Thu Jul 22 23:08:54 CEST 2004
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This might help:
c = 1 for p0 in range(0, 7): for p1 in range(p0, 12): for p2 in range(p1, 12): for p3 in range(p2, 12): for p4 in range(p3, 12): for p5 in range(p4, 12): print repr(c).rjust(3), "\t", print "%X %X %X %X %X %X" % (p0, p1, p2, p3, p4, p5) c += 1
Not sure what the c increment does but I'll leave it in!
print "...Done"
Ultimately you have to generate all the permutations but by eliminating the ones you already know are invalid it should speed it up a bit.
Alan G.
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