Issue 33448: Output_Typo_Error - Python tracker (original) (raw)

Issue33448

Created on 2018-05-09 17:02 by vishva_11, last changed 2022-04-11 14:59 by admin. This issue is now closed.

Messages (3)
msg316325 - (view)	Author: vishva patel (vishva_11)	Date: 2018-05-09 17:02
There is an out[ut typo error in the documentation of python in the module (An Informal Introductio To Python) 3.1.2 section Strings the first example last output the output of: >>>Isn\'t is given as Isn\t #but it shuld be >>>Isn\'t Isn't so fix it
msg316326 - (view)	Author: Mark Dickinson (mark.dickinson) *	Date: 2018-05-09 17:30
I can't reproduce. I'm looking at https://docs.python.org/3.6/tutorial/introduction.html#strings, and when I test things in Python 3.6.5, I see exactly the same output as given in the documentation: Python 3.6.5 (default, Mar 29 2018, 15:37:32) [GCC 4.2.1 Compatible Apple LLVM 9.0.0 (clang-900.0.39.2)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> '"Isn\'t," she said.' '"Isn\'t," she said.' >>> '"Isn\'t," she said.' '"Isn\'t," she said.' >>> print('"Isn\'t," she said.') "Isn't," she said. Please could you clarify? Perhaps you could copy and paste from an example interpreter session on your machine showing what you're seeing?
msg316370 - (view)	Author: Mark Dickinson (mark.dickinson) *	Date: 2018-05-10 17:20
Marking as pending; we can't take this forward without more input from the OP. As far as I can tell, the documentation is perfectly correct here: I suspect that there was a misunderstanding somewhere along the line.