11786 – [3.3/3.4 regression] operator() call on variable in other namespace not recognized (original) (raw)

GCC rejects the following valid code:

struct S { template void operator() (T) {} };

namespace N { S s; struct A {} a; }

using N::s;

void f () { s(N::a); }

GCC says:

t.cpp:8: error: N::s' is not a function, t.cpp:8: error: conflict with N::s' t.cpp:14: error: in call to `s'

My best guess would be that GCC does not recognize s(..) as a call to operator() on variable N::s, and as such insists on finding a function named 'N::s'. I haven't got a clue as to what the rest of the error message indicates or how A is involved.

Comeau compiles the code without problems.

I'm using GCC 3.4 20030723.

Comment 1 Eelis 2003-08-04 07:28:00 UTC

Simplified snippet:

namespace N { struct A {}; struct S { void operator() (A); } s; }

using N::s;

void f () { s(N::A()); }

Comment 2 Drea Pinski 2003-08-04 19:46:42 UTC

I can confirm this on the mainline (20030804). ICC 6.0 in strict mode (-Xc) accepts this code.

Comment 3 Volker Reichelt 2003-08-04 23:02:14 UTC

gcc 2.95.x compiled the code. It is rejected since gcc 3.0.

Comment 6 Mark Mitchell 2003-09-08 19:15:32 UTC

Fixed in GCC 3.3.2, GCC 3.4.