groupby transform producing different results depending on whether a lambda function was passed or a numpy function was passed · Issue #14457 · pandas-dev/pandas (original) (raw)

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@pirsquared

Description

@pirsquared

stackoverflow
http://stackoverflow.com/q/40141881/2336654

import pandas as pd import numpy as np

df = pd.DataFrame(dict(A=['a', 'a'], B=[0, 1])) print(df.groupby('A').transform(np.mean))

is no the same as

print(df.groupby('A').transform(lambda x: np.mean(x)))

Output of pd.show_versions()

## INSTALLED VERSIONS

commit: None
python: 3.5.2.final.0
python-bits: 64
OS: Darwin
OS-release: 15.5.0
machine: x86_64
processor: i386
byteorder: little
LC_ALL: None
LANG: en_US.UTF-8
LOCALE: en_US.UTF-8

pandas: 0.19.0
nose: 1.3.7
pip: 8.1.2
setuptools: 27.2.0
Cython: 0.24.1
numpy: 1.11.1
scipy: 0.18.1
statsmodels: 0.6.1
xarray: None
IPython: 5.1.0
sphinx: 1.4.6
patsy: 0.4.1
dateutil: 2.5.3
pytz: 2016.6.1
blosc: None
bottleneck: 1.1.0
tables: 3.2.3.1
numexpr: 2.6.1
matplotlib: 1.5.3
openpyxl: 2.3.2
xlrd: 1.0.0
xlwt: 1.1.2
xlsxwriter: 0.9.3
lxml: 3.6.4
bs4: 4.5.1
html5lib: None
httplib2: None
apiclient: None
sqlalchemy: 1.0.13
pymysql: None
psycopg2: None
jinja2: 2.8
boto: 2.42.0
pandas_datareader: 0.2.1