BUG: Regression on DataFrame.from_records · Issue #42456 · pandas-dev/pandas (original) (raw)
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- I have confirmed this bug exists on the latest version of pandas.
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Code Sample, a copy-pastable example
from numpy import empty, array from pandas import DataFrame
structured_dtype = [('prop', int)]
Does NOT work any more
result = empty((0, len(structured_dtype))) structured_array = array(result, dtype=structured_dtype) DataFrame.from_records(structured_array)
Triggers: ValueError: If using all scalar values, you must pass an index
.
Problem description
This previously worked on Pandas version 1.2.5.
Expected Output
No exception.
Output of pd.show_versions()
INSTALLED VERSIONS
commit : f00ed8f
python : 3.8.10.final.0
python-bits : 64
OS : Linux
OS-release : 5.4.0-77-generic
Version : #86-Ubuntu SMP Thu Jun 17 02:35:03 UTC 2021
machine : x86_64
processor : x86_64
byteorder : little
LC_ALL : None
LANG : en_US.UTF-8
LOCALE : en_US.UTF-8
pandas : 1.3.0
numpy : 1.21.0
pytz : 2021.1
dateutil : 2.8.1
pip : 20.0.2
setuptools : 57.0.0
Cython : None
pytest : 6.2.4
hypothesis : 6.14.0
sphinx : 4.0.2
blosc : None
feather : None
xlsxwriter : None
lxml.etree : None
html5lib : None
pymysql : None
psycopg2 : None
jinja2 : 3.0.1
IPython : None
pandas_datareader: None
bs4 : None
bottleneck : None
fsspec : None
fastparquet : None
gcsfs : None
matplotlib : 3.4.2
numexpr : 2.7.3
odfpy : None
openpyxl : None
pandas_gbq : None
pyarrow : None
pyxlsb : None
s3fs : None
scipy : 1.7.0
sqlalchemy : None
tables : 3.6.1
tabulate : None
xarray : None
xlrd : None
xlwt : None
numba : None