Bubble Sort in Elixir (original) (raw)
Published on 03 October 2019 (Updated: 16 October 2019)
Welcome to the Bubble Sort in Elixir page! Here, you'll find the source code for this program as well as a description of how the program works.
Current Solution
defmodule Bubble do
@doc """
Sort the giveen input using bubble sort
"""
def main(args) do
cond do
length(args) != 1
or List.first(args) == ""
or List.first(args) |> String.split(",") |> length < 2 ->
IO.puts("Usage: please provide a list of at least two integers to sort in the format \"1, 2, 3, 4, 5\"")
true ->
input = List.first(args)
|> String.split(",")
|> Enum.map(&String.trim/1)
|> Enum.map(&String.to_integer/1)
sorted_list = pass(input, [])
IO.puts(Enum.join(sorted_list, ", "))
end
end
@doc """
Handle each pass, return the list when there are no more changes to the list
"""
def pass(new_list, old_list) when new_list == old_list, do: new_list
def pass(new_list, old_list) when new_list != old_list do
passed_list = sort(new_list, [])
pass(passed_list, new_list)
end
@doc """
Add the smaller element to accumulator, recursively call sort until all elements are added to accumulator
"""
def sort([], acc), do: acc
def sort([head, tail], acc) do
if head > tail, do: sort([], acc ++ [tail, head]), else: sort([], acc ++ [head, tail])
end
def sort([head | [head2 | tail]], acc) do
if head > head2, do: sort([head | tail], acc ++ [head2]), else: sort([head2 | tail], acc ++ [head])
end
end
Bubble.main(System.argv())
Bubble Sort in Elixir was written by:
- Jeremy Grifski
- Sree Siva Sandeep Palaparthi
If you see anything you'd like to change or update, please consider contributing.
How to Implement the Solution
No 'How to Implement the Solution' section available. Please consider contributing.
How to Run the Solution
No 'How to Run the Solution' section available. Please consider contributing.