tf.math.is_strictly_increasing  |  TensorFlow v2.0.0 (original) (raw)

tf.math.is_strictly_increasing

Returns True if x is strictly increasing.

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Compat aliases for migration

SeeMigration guide for more details.

tf.compat.v1.debugging.is_strictly_increasing, tf.compat.v1.is_strictly_increasing, tf.compat.v1.math.is_strictly_increasing

tf.math.is_strictly_increasing(
    x, name=None
)

Elements of x are compared in row-major order. The tensor [x[0],...]is strictly increasing if for every adjacent pair we have x[i] < x[i+1]. If x has less than two elements, it is trivially strictly increasing.

See also: is_non_decreasing

Args
x Numeric Tensor.
name A name for this operation (optional). Defaults to "is_strictly_increasing"
Returns
Boolean Tensor, equal to True iff x is strictly increasing.
Raises
TypeError if x is not a numeric tensor.

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Last updated 2020-10-01 UTC.