Finite Groups Whose Minimal Subgroups are Weakly -SUBGROUPS (original) (raw)
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Suppose that G is a finite group and H , K are subgroups of G. We say that H is weakly closed in K with respect to G if, for any g ∈ G such that H g ≤ K , we have H g = H. In particular, when H is a subgroup of prime-power order and K is a Sylow subgroup containing it, H is simply said to be a weakly closed subgroup of G or weakly closed in G. In the paper, we investigate the structure of finite groups by means of weakly closed subgroups.
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On minimal non-p-closed groups and related properties
Publicationes Mathematicae Debrecen, 2011
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Subgroups close to normal subgroups
Journal of Algebra, 1989
Let G be a group and H a subgroup. It is shown that the set of indices {[H:HngHg~l] | geG) has a finite upper bound n if and only if there is a normal subgroup N < G which is commensurable with //; i.e., such that [H:Nr\H] and [N:Nr>H] are finite; moreover, the latter indices admit bounds depending only on n. If the bounded index hypothesis is assumed only for g running over some subgroup K<G, the conclusion holds with "normal" weakened to "normalized by K". More detailed Information is gölten under the assumption that {[//://ngHg~l] | geG} = {!,/>} for p prime. In particular, when p = 2 there exists N < G such that either H has index 2 in 7V, or N has index 2 in H. 1. THE {l,p} CASE This section contains the results referred to in the second paragraph of the abstract. The main results of the first paragraph are obtained in §2, which may be read independently. In the last three sections we extend both sets of results to the "normalized by K" context, obtain some modified bounds, and note some examples. We begin with the result that started this investigation. THEOREM l. Let G be a group, and H a subgroup. Then [H:Hr\gHg~l] <2 for all geG if and only if G has a normal subgroup N such that either (a) H < N and [N:H] < 2, or (b) N < H and [H:N] <2. Proof. "If" is clear. We shall prove "only if". Let X denote the set of conjugates of H. We observe that there are no proper inclusion relations among members of X, since if χ properly contained gxg~l, the latter would have index 2 in x, hence g 2 xg~ would have index 4 in x, a contradiction. Thus, if two members of X are distinct, their intersection has index 2 in each. Let us now choose any xeX and define two equivalence relations, [x] and , on X-{x}, letting y[x}z mean yr\x = zr>x, and yz mean yx = zx (equality of subsets). We Claim *This work was done while the authors were partly supported by NSF contracts DMS 85-02330 and DMS 87-06176 respectively. Electronic mail addresses of the authors at cartan.Berkeley.Edu or ucbcarta.bitnet: Bergman: gbergman, Lenstra: hwl.