ispunct() function in C (original) (raw)

Last Updated : 16 Dec, 2021

The ispunct() function checks whether a character is a punctuation character or not. The term "punctuation" as defined by this function includes all printable characters that are neither alphanumeric nor a space. For example '@', '$', etc. This function is defined in ctype.h header file.

syntax:

int ispunct(int ch); ch: character to be checked. Return Value : function return nonzero if character is a punctuation character; otherwise zero is returned.

CPP `

// Program to check punctuation #include <stdio.h> #include <ctype.h> int main() { // The punctuations in str are '!' and ',' char str[] = "welcome! to GeeksForGeeks, ";

int i = 0, count = 0;
while (str[i]) {
    if (ispunct(str[i]))
        count++;
    i++;
}
printf("Sentence contains %d punctuation"
       " characters.\n", count);
return 0;

}

`

Output:

Sentence contains 2 punctuation characters.

CPP `

// C program to print all Punctuations #include <stdio.h> #include <ctype.h> int main() { int i; printf("All punctuation characters in C" " programming are: \n"); for (i = 0; i <= 255; ++i) if (ispunct(i) != 0) printf("%c ", i); return 0; }

`

Output:

All punctuation characters in C programming are: ! " # $ % & ' ( ) * +, - . / : ; ? @ [ \ ] ^ _ ` { | } ~