Class getGenericSuperclass() method in Java with Examples (original) (raw)

Last Updated : 02 Aug, 2021

The getGenericSuperclass() method of java.lang.Class class is used to get the type of the superclass of this entity. This entity can be a class, an array, an interface, etc. The method returns the type of the superclass of this entity.
Syntax:

public Type getGenericSuperclass()

Parameter: This method does not accept any parameter.
Return Value: This method returns the type of the superclass of this entity.
Exceptions: This method throws following exceptions:

• GenericSignatureFormatError: if the generic class signature does not conform to the format specified in The Java™ Virtual Machine Specification
• TypeNotPresentException: if the generic superclass refers to a non-existent type declaration
• MalformedParameterizedTypeException: if the generic superclass refers to a parameterized type that cannot be instantiated for any reason

Below programs demonstrate the getGenericSuperclass() method.
Example 1:

Java

public class Test {

`` public static void main(String[] args)

`` throws ClassNotFoundException

`` {

`` Class myClass = Class.forName( "Test" );

`` System.out.println(

`` "Class represented by myClass: "

`` + myClass.toString());

`` System.out.println(

`` "Type of the superclass of myClass: "

`` + myClass.getGenericSuperclass());

`` }

}

Output:

Class represented by myClass: class Test Type of the superclass of myClass: class java.lang.Object

Example 2:

Java

public class Test {

`` class Arr {

`` }

`` public static void main(String[] args)

`` throws ClassNotFoundException

`` {

`` Class arrClass = Arr. class ;

`` System.out.println(

`` "Type of the superclass of arrClass: "

`` + arrClass.getGenericSuperclass());

`` }

}

Output:

Type of the superclass of arrClass: class java.lang.Object

Reference: https://docs.oracle.com/javase/9/docs/api/java/lang/Class.html#getGenericSuperclass–

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