Introduction of KMap (Karnaugh Map) (original) (raw)

Last Updated : 8 Sep, 2025

In many digital circuits and practical problems, we need to find expressions with minimum variables. We can minimize Boolean expressions of 3, 4 variables very easily using K-map without using any Boolean algebra theorems. It is a tool which is used in digital logic to simplify boolean expression. It helps to simplify logic into simpler form by organizing grid from truth table values. This helps it to create a minimal Boolean expressions by identifying patterns.

K-map can take two forms:

  1. Sum of product (SOP)
  2. Product of Sum (POS)

According to the need of problem. K-map is a table-like representation, but it gives more information than the TABLE. We fill a grid of the K-map with 0’s and 1’s then solve it by making groups.

**Steps to Solve Expression using K-map

  1. Select the K-map according to the number of variables.
  2. Identify minterms or maxterms as given in the problem.
  3. For SOP put 1’s in blocks of K-map respective to the minterms (0’s elsewhere).
  4. For POS put 0’s in blocks of K-map respective to the max terms (1’s elsewhere).
  5. Make rectangular groups containing total terms in power of two like 2,4,8 ..(except 1) and try to cover as many elements as you can in one group.
  6. From the groups made in step 5 find the product terms and sum them up for SOP form.

**SOP FORM(Sum of Product Form)

SOP form is way to simplify and write Boolean expressions using AND to combine inputs and OP to combine the results.

1. K-map for 2 variables

In the 2 variable k-map, four squares are constructed. Each square contains one term of expression with two variables.

K-map for 2 variables

K-Map for 2 variables

**2. K-map of 3 variables

K-map SOP form for 3 variables

Z= ΣA,B,C(1,3,6,7) 

SOP

From **red group we get product term:

A’C

From green group we get product term:

AB

Summing these product terms we get- **Final expression (A’C+AB)

**3. K-map for 4 variables

K-map 4 variable SOP form

K-map 4 variable SOP form

F(A,B,C,D)=Σ(0,1,2,3,12,13,15,14)

k_map

k map 4 variables

From **red group we get product term:

AB

From **green group we get product term:

A'B'

Summing these product terms we get- **Final expression (AB+A’B').

**POS FORM (Product of Sum Form)

POS form is a way to simplify and write Boolean expressions using OR to combine terms inside parentheses and then AND to combine those groups.

1.K-map of 2 variables

In the 2 variable k-map, four squares are constructed. Each square contains one term of expression with two variables.

K-map of 2 variables

K-map of 2 variables

**2. K-map of 3 variables

POS

K-map 3 variable POS form

F(A,B,C)=Σ(0,3,6,7)

POS

From **red group we find terms

A    B   

Taking complement of these two

A'     B'   

Now **sum up them

(A' + B') 

From brown group we find terms

B   C 

Taking complement of these two terms

B’  C’ 

Now sum up them

(B’+C’) 

From **yellow group we find terms

A' B' C’ 

Taking complement of these two

A B C 

Now **sum up them

(A + B + C) 

We will take product of these three terms : **Final expression -

****(A' + B’) (B’ + C’) (A + B + C)** 

**3. K-map of 4 variables

4 variables

K-map 4 variable POS form

F(A,B,C,D)=Σ(3,5,7,8,10,11,12,13) 

From **green group we find terms

C’  D  B 

Taking their complement and summing them

(C+D’+B’) 

From **red group we find terms

C  D  A’ 

Taking their complement and summing them

(C’+D’+A) 

From **blue group we find terms

A  C’  D’ 

Taking their complement and summing them

(A’+C+D) 

From **brown group we find terms

A  B’  C 

Taking their complement and summing them

(A’+B+C’) 

Finally we express these as product -

****(C+D’+B’).(C’+D’+A).(A’+C+D).(A’+B+C’)** 

Advantages of K-MAP

Disadvantages of K-MAP

**Also attempt **Quiz on K-MAP .