Check if a graph is Strongly, Unilaterally or Weakly connected (original) (raw)
Last Updated : 15 Jul, 2025
Given an unweighted directed graph G as a path matrix, the task is to find out if the graph is Strongly Connected or Unilaterally Connected or Weakly Connected.
- Strongly Connected: A graph is said to be strongly connected if every pair of vertices(u, v) in the graph contains a path between each other. In an unweighted directed graph G, every pair of vertices u and v should have a path in each direction between them i.e., bidirectional path. The elements of the path matrix of such a graph will contain all 1's.
- Unilaterally Connected: A graph is said to be unilaterally connected if it contains a directed path from u to v OR a directed path from v to u for every pair of vertices u, v. Hence, at least for any pair of vertices, one vertex should be reachable form the other. Such a path matrix would rather have upper triangle elements containing 1's OR lower triangle elements containing 1's.
- Weakly Connected: A directed graph is weakly connected if there is a path between every two vertices in the underlying undirected graph (i.e, the graph formed when the direction of the edges are removed).
Examples:
Input: Below is the given graph with path matrix:
Output: Strongly Connected Graph
Input: Below is the given graph with path matrix:
Output: Unilaterally Connected Graph
Input: Below is the given graph with path matrix:
Output: Weakly Connected Graph
Approach:
- For the graph to be Strongly Connected, traverse the given path matrix using the approach discussed in this article check whether all the values in the cell are 1 or not. If yes then print "Strongly Connected Graph" else check for the other two graphs.
- For the graph to be Unilaterally Connected, traverse the given path matrix using the approach discussed in this article and check the following:
- If all the values above the main diagonal are 1s and all the values other than that are 0s.
- If all the values below the main diagonal are 1s and all the values other than that are 0s.
- If one of the above two conditions satisfies then the given graph is Unilaterally Connected else the graph is Weakly Connected Graph.
Below is the implementation of the above approach:
C++ `
// C++ implementation of the approach
#include <bits/stdc++.h> using namespace std; #define V 3
// Function to find the characteristic // of the given graph int checkConnected(int graph[][V], int n) {
// Check whether the graph is
// strongly connected or not
bool strongly = true;
// Traverse the path matrix
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
// If all the elements are
// not equal then the graph
// is not strongly connected
if (graph[i][j] != graph[j][i]) {
strongly = false;
break;
}
}
// Break out of the loop if false
if (!strongly) {
break;
}
}
// If true then print strongly
// connected and return
if (strongly) {
cout << "Strongly Connected";
return 0;
}
// Check whether the graph is
// Unilaterally connected by
// checking Upper Triangle element
bool uppertri = true;
// Traverse the path matrix
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
// If uppertriangle elements
// are 0 then break out of the
// loop and check the elements
// of lowertriangle matrix
if (i > j && graph[i][j] == 0) {
uppertri = false;
break;
}
}
// Break out of the loop if false
if (!uppertri) {
break;
}
}
// If true then print unilaterally
// connected and return
if (uppertri) {
cout << "Unilaterally Connected";
return 0;
}
// Check lowertraingle elements
bool lowertri = true;
// Traverse the path matrix
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
// If lowertraingle elements
// are 0 then break cause
// 1's are expected
if (i < j && graph[i][j] == 0) {
lowertri = false;
break;
}
}
// Break out of the loop if false
if (!lowertri) {
break;
}
}
// If true then print unilaterally
// connected and return
if (lowertri) {
cout << "Unilaterally Connected";
return 0;
}
// If elements are in random order
// unsynchronized then print weakly
// connected and return
else {
cout << "Weakly Connected";
}
return 0;}
// Driver Code int main() { // Number of nodes int n = 3;
// Given Path Matrix
int graph[V][V] = {
{ 0, 1, 1 },
{ 0, 0, 1 },
{ 0, 0, 0 },
};
// Function Call
checkConnected(graph, n);
return 0;}
Java
// Java implementation of the above approach import java.util.*;
class GFG {
static final int V = 3;
// Function to find the characteristic
// of the given graph
static int checkConnected(int graph[][], int n)
{
// Check whether the graph is
// strongly connected or not
boolean strongly = true;
// Traverse the path matrix
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
// If all the elements are
// not equal then the graph
// is not strongly connected
if (graph[i][j] != graph[j][i]) {
strongly = false;
break;
}
}
// Break out of the loop if false
if (!strongly) {
break;
}
}
// If true then print strongly
// connected and return
if (strongly) {
System.out.print("Strongly Connected");
return 0;
}
// Check whether the graph is
// Unilaterally connected by
// checking Upper Triangle element
boolean uppertri = true;
// Traverse the path matrix
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
// If uppertriangle elements
// are 0 then break out of the
// loop and check the elements
// of lowertriangle matrix
if (i > j && graph[i][j] == 0) {
uppertri = false;
break;
}
}
// Break out of the loop if false
if (!uppertri) {
break;
}
}
// If true then print unilaterally
// connected and return
if (uppertri) {
System.out.print("Unilaterally Connected");
return 0;
}
// Check lowertraingle elements
boolean lowertri = true;
// Traverse the path matrix
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
// If lowertraingle elements
// are 0 then break cause
// 1's are expected
if (i < j && graph[i][j] == 0) {
lowertri = false;
break;
}
}
// Break out of the loop if false
if (!lowertri) {
break;
}
}
// If true then print unilaterally
// connected and return
if (lowertri) {
System.out.print("Unilaterally Connected");
return 0;
}
// If elements are in random order
// unsynchronized then print weakly
// connected and return
else {
System.out.print("Weakly Connected");
}
return 0;
}
// Driver Code
public static void main(String[] args)
{
// Number of nodes
int n = 3;
// Given Path Matrix
int graph[][]
= { { 0, 1, 1 }, { 0, 0, 1 }, { 0, 0, 0 } };
// Function call
checkConnected(graph, n);
}}
// This code is contributed by 29AjayKumar
Python3
Python3 implementation of
the above approach
V = 3
Function to find the
characteristic of the
given graph
def checkConnected(graph, n):
# Check whether the graph is
# strongly connected or not
strongly = True
# Traverse the path
# matrix
for i in range(n):
for j in range(n):
# If all the elements are
# not equal then the graph
# is not strongly connected
if (graph[i][j] != graph[j][i]):
strongly = False
break
# Break out of the
# loop if false
if not strongly:
break
# If true then print
# strongly connected and return
if (strongly):
print("Strongly Connected")
exit()
# Check whether the graph is
# Unilaterally connected by
# checking Upper Triangle element
uppertri = True
# Traverse the path matrix
for i in range(n):
for j in range(n):
# If uppertriangle elements
# are 0 then break out of the
# loop and check the elements
# of lowertriangle matrix
if (i > j and graph[i][j] == 0):
uppertri = False
break
# Break out of the
# loop if false
if not uppertri:
break
# If true then print
# unilaterally connected
# and return
if uppertri:
print("Unilaterally Connected")
exit()
# Check lowertraingle elements
lowertri = True
# Traverse the path matrix
for i in range(n):
for j in range(n):
# If lowertraingle elements
# are 0 then break cause
# 1's are expected
if (i < j and graph[i][j] == 0):
lowertri = False
break
# Break out of the
# loop if false
if not lowertri:
break
# If true then print
# unilaterally connected
# and return
if lowertri:
print("Unilaterally Connected")
exit()
# If elements are in random order
# unsynchronized then print weakly
# connected and return
else:
print("Weakly Connected")
exit()if name == "main":
# Number of nodes
n = 3
# Given Path Matrix
graph = [[0, 1, 1],
[0, 0, 1],
[0, 0, 0]]
# Function Call
checkConnected(graph, n)This code is contributed by rutvik_56
C#
// C# implementation of the above approach using System;
class GFG {
// static readonly int V = 3;
// Function to find the characteristic
// of the given graph
static int checkConnected(int[, ] graph, int n)
{
// Check whether the graph is
// strongly connected or not
bool strongly = true;
// Traverse the path matrix
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
// If all the elements are
// not equal then the graph
// is not strongly connected
if (graph[i, j] != graph[j, i]) {
strongly = false;
break;
}
}
// Break out of the loop if false
if (!strongly) {
break;
}
}
// If true then print strongly
// connected and return
if (strongly) {
Console.Write("Strongly Connected");
return 0;
}
// Check whether the graph is
// Unilaterally connected by
// checking Upper Triangle element
bool uppertri = true;
// Traverse the path matrix
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
// If uppertriangle elements
// are 0 then break out of the
// loop and check the elements
// of lowertriangle matrix
if (i > j && graph[i, j] == 0) {
uppertri = false;
break;
}
}
// Break out of the loop if false
if (!uppertri) {
break;
}
}
// If true then print unilaterally
// connected and return
if (uppertri) {
Console.Write("Unilaterally Connected");
return 0;
}
// Check lowertraingle elements
bool lowertri = true;
// Traverse the path matrix
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
// If lowertraingle elements
// are 0 then break cause
// 1's are expected
if (i < j && graph[i, j] == 0) {
lowertri = false;
break;
}
}
// Break out of the loop if false
if (!lowertri) {
break;
}
}
// If true then print unilaterally
// connected and return
if (lowertri) {
Console.Write("Unilaterally Connected");
return 0;
}
// If elements are in random order
// unsynchronized then print weakly
// connected and return
else {
Console.Write("Weakly Connected");
}
return 0;
}
// Driver Code
public static void Main(String[] args)
{
// Number of nodes
int n = 3;
// Given Path Matrix
int[, ] graph
= { { 0, 1, 1 }, { 0, 0, 1 }, { 0, 0, 0 } };
// Function call
checkConnected(graph, n);
}}
// This code is contributed by 29AjayKumar
JavaScript
`
Output
Unilaterally Connected
Time Complexity: O(N2)
Auxiliary Space: O(1)