Implement a Phone Directory (original) (raw)
Last Updated : 2 Mar, 2023
Given a list of contacts that exist in a phone directory. The task is to implement a search query for the phone directory. The search query on a string ‘str’ displays all the contacts which prefixes as ‘str’. One special property of the search function is that when a user searches for a contact from the contact list then suggestions (Contacts with prefix as the string entered so for) are shown after user enters each character.
Note: Contacts in the list consist of only lowercase alphabets. Example:
Input : contacts [] = {“gforgeeks” , “geeksquiz” } Query String = “gekk”
Output : Suggestions based on "g" are geeksquiz gforgeeks
Suggestions based on "ge" are
geeksquiz
No Results Found for "gek"
No Results Found for "gekk" Recommended: Please solve it on “_PRACTICE_ ” first, before moving on to the solution.
Phone Directory can be efficiently implemented using Trie Data Structure. We insert all the contacts into Trie. Generally search query on a Trie is to determine whether the string is present or not in the trie, but in this case we are asked to find all the strings with each prefix of ‘str’. This is equivalent to doing a DFS traversal on a graph. From a Trie node, visit adjacent Trie nodes and do this recursively until there are no more adjacent. This recursive function will take 2 arguments one as Trie Node which points to the current Trie Node being visited and other as the string which stores the string found so far with prefix as ‘str’. Each Trie Node stores a boolean variable ‘isLast’ which is true if the node represents end of a contact(word).
// This function displays all words with given // prefix. "node" represents last node when // path from root follows characters of "prefix". displayContacts (TreiNode node, string prefix) If (node.isLast is true) display prefix
// finding adjacent nodes
for each character ‘i’ in lower case Alphabets
if (node.child[i] != NULL)
displayContacts(node.child[i], prefix+i)User will enter the string character by character and we need to display suggestions with the prefix formed after every entered character. So one approach to find the prefix starting with the string formed is to check if the prefix exists in the Trie, if yes then call the displayContacts() function. In this approach after every entered character we check if the string exists in the Trie. Instead of checking again and again, we can maintain a pointer prevNode' that points to the TrieNode which corresponds to the last entered character by the user, now we need to check the child node for the 'prevNode' when user enters another character to check if it exists in the Trie. If the new prefix is not in the Trie, then all the string which are formed by entering characters after 'prefix' can't be found in Trie too. So we break the loop that is being used to generate prefixes one by one and print "No Result Found" for all remaining characters.
C++ `
// C++ Program to Implement a Phone // Directory Using Trie Data Structure #include <bits/stdc++.h> using namespace std;
struct TrieNode { // Each Trie Node contains a Map 'child' // where each alphabet points to a Trie // Node. // We can also use a fixed size array of // size 256. unordered_map<char, TrieNode*> child;
// 'isLast' is true if the node represents
// end of a contact
bool isLast;
// Default Constructor
TrieNode()
{
// Initialize all the Trie nodes with NULL
for (char i = 'a'; i <= 'z'; i++)
child[i] = NULL;
isLast = false;
}};
// Making root NULL for ease so that it doesn't // have to be passed to all functions. TrieNode* root = NULL;
// Insert a Contact into the Trie void insert(string s) { int len = s.length();
// 'itr' is used to iterate the Trie Nodes
TrieNode* itr = root;
for (int i = 0; i < len; i++) {
// Check if the s[i] is already present in
// Trie
TrieNode* nextNode = itr->child[s[i]];
if (nextNode == NULL) {
// If not found then create a new TrieNode
nextNode = new TrieNode();
// Insert into the Map
itr->child[s[i]] = nextNode;
}
// Move the iterator('itr') ,to point to next
// Trie Node
itr = nextNode;
// If its the last character of the string 's'
// then mark 'isLast' as true
if (i == len - 1)
itr->isLast = true;
}}
// This function simply displays all dictionary words // going through current node. String 'prefix' // represents string corresponding to the path from // root to curNode. void displayContactsUtil(TrieNode* curNode, string prefix) { // Check if the string 'prefix' ends at this Node // If yes then display the string found so far if (curNode->isLast) cout << prefix << endl;
// Find all the adjacent Nodes to the current
// Node and then call the function recursively
// This is similar to performing DFS on a graph
for (char i = 'a'; i <= 'z'; i++) {
TrieNode* nextNode = curNode->child[i];
if (nextNode != NULL)
displayContactsUtil(nextNode, prefix + (char)i);
}}
// Display suggestions after every character enter by // the user for a given query string 'str' void displayContacts(string str) { TrieNode* prevNode = root;
string prefix = "";
int len = str.length();
// Display the contact List for string formed
// after entering every character
int i;
for (i = 0; i < len; i++) {
// 'prefix' stores the string formed so far
prefix += (char)str[i];
// Get the last character entered
char lastChar = prefix[i];
// Find the Node corresponding to the last
// character of 'prefix' which is pointed by
// prevNode of the Trie
TrieNode* curNode = prevNode->child[lastChar];
// If nothing found, then break the loop as
// no more prefixes are going to be present.
if (curNode == NULL) {
cout << "\nNo Results Found for " << prefix
<< "\n";
i++;
break;
}
// If present in trie then display all
// the contacts with given prefix.
cout << "\nSuggestions based on " << prefix
<< "are ";
displayContactsUtil(curNode, prefix);
// Change prevNode for next prefix
prevNode = curNode;
}
// Once search fails for a prefix, we print
// "Not Results Found" for all remaining
// characters of current query string "str".
for (; i < len; i++) {
prefix += (char)str[i];
cout << "\nNo Results Found for " << prefix << "\n";
}}
// Insert all the Contacts into the Trie void insertIntoTrie(string contacts[], int n) { // Initialize root Node root = new TrieNode();
// Insert each contact into the trie
for (int i = 0; i < n; i++)
insert(contacts[i]);}
// Driver program to test above functions int main() { // Contact list of the User string contacts[] = { "gforgeeks", "geeksquiz" };
// Size of the Contact List
int n = sizeof(contacts) / sizeof(string);
// Insert all the Contacts into Trie
insertIntoTrie(contacts, n);
string query = "gekk";
// Note that the user will enter 'g' then 'e', so
// first display all the strings with prefix as 'g'
// and then all the strings with prefix as 'ge'
displayContacts(query);
return 0;}
Java
// Java Program to Implement a Phone // Directory Using Trie Data Structure import java.util.*;
class TrieNode { // Each Trie Node contains a Map 'child' // where each alphabet points to a Trie // Node. HashMap<Character,TrieNode> child;
// 'isLast' is true if the node represents
// end of a contact
boolean isLast;
// Default Constructor
public TrieNode()
{
child = new HashMap<Character,TrieNode>();
// Initialize all the Trie nodes with NULL
for (char i = 'a'; i <= 'z'; i++)
child.put(i,null);
isLast = false;
}}
class Trie { TrieNode root;
// Insert all the Contacts into the Trie
public void insertIntoTrie(String contacts[])
{
root = new TrieNode();
int n = contacts.length;
for (int i = 0; i < n; i++)
{
insert(contacts[i]);
}
}
// Insert a Contact into the Trie
public void insert(String s)
{
int len = s.length();
// 'itr' is used to iterate the Trie Nodes
TrieNode itr = root;
for (int i = 0; i < len; i++)
{
// Check if the s[i] is already present in
// Trie
TrieNode nextNode = itr.child.get(s.charAt(i));
if (nextNode == null)
{
// If not found then create a new TrieNode
nextNode = new TrieNode();
// Insert into the HashMap
itr.child.put(s.charAt(i),nextNode);
}
// Move the iterator('itr') ,to point to next
// Trie Node
itr = nextNode;
// If its the last character of the string 's'
// then mark 'isLast' as true
if (i == len - 1)
itr.isLast = true;
}
}
// This function simply displays all dictionary words
// going through current node. String 'prefix'
// represents string corresponding to the path from
// root to curNode.
public void displayContactsUtil(TrieNode curNode,
String prefix)
{
// Check if the string 'prefix' ends at this Node
// If yes then display the string found so far
if (curNode.isLast)
System.out.println(prefix);
// Find all the adjacent Nodes to the current
// Node and then call the function recursively
// This is similar to performing DFS on a graph
for (char i = 'a'; i <= 'z'; i++)
{
TrieNode nextNode = curNode.child.get(i);
if (nextNode != null)
{
displayContactsUtil(nextNode, prefix + i);
}
}
}
// Display suggestions after every character enter by
// the user for a given string 'str'
void displayContacts(String str)
{
TrieNode prevNode = root;
// 'flag' denotes whether the string entered
// so far is present in the Contact List
String prefix = "";
int len = str.length();
// Display the contact List for string formed
// after entering every character
int i;
for (i = 0; i < len; i++)
{
// 'str' stores the string entered so far
prefix += str.charAt(i);
// Get the last character entered
char lastChar = prefix.charAt(i);
// Find the Node corresponding to the last
// character of 'str' which is pointed by
// prevNode of the Trie
TrieNode curNode = prevNode.child.get(lastChar);
// If nothing found, then break the loop as
// no more prefixes are going to be present.
if (curNode == null)
{
System.out.println("\nNo Results Found for "
+ prefix);
i++;
break;
}
// If present in trie then display all
// the contacts with given prefix.
System.out.println("\nSuggestions based on "
+ prefix + " are ");
displayContactsUtil(curNode, prefix);
// Change prevNode for next prefix
prevNode = curNode;
}
for ( ; i < len; i++)
{
prefix += str.charAt(i);
System.out.println("\nNo Results Found for "
+ prefix);
}
}}
// Driver code class Main { public static void main(String args[]) { Trie trie = new Trie();
String contacts [] = {"gforgeeks", "geeksquiz"};
trie.insertIntoTrie(contacts);
String query = "gekk";
// Note that the user will enter 'g' then 'e' so
// first display all the strings with prefix as 'g'
// and then all the strings with prefix as 'ge'
trie.displayContacts(query);
}}
Python3
Python Program to Implement a Phone
Directory Using Trie Data Structure
class TrieNode: def init(self):
# Each Trie Node contains a Map 'child'
# where each alphabet points to a Trie
# Node.
self.child = {}
self.is_last = FalseMaking root NULL for ease so that it doesn't
have to be passed to all functions.
root = TrieNode()
Insert a Contact into the Trie
def insert(string):
# 'itr' is used to iterate the Trie Nodes
itr = root
for char in string:
# Check if the s[i] is already present in
# Trie
if char not in itr.child:
# If not found then create a new TrieNode
itr.child[char] = TrieNode()
# Move the iterator('itr') ,to point to next
# Trie Node
itr = itr.child[char]
# If its the last character of the string 's'
# then mark 'isLast' as true
itr.is_last = TrueThis function simply displays all dictionary words
going through current node. String 'prefix'
represents string corresponding to the path from
root to curNode.
def display_contacts_util(cur_node, prefix):
# Check if the string 'prefix' ends at this Node
# If yes then display the string found so far
if cur_node.is_last:
print(prefix)
# Find all the adjacent Nodes to the current
# Node and then call the function recursively
# This is similar to performing DFS on a graph
for i in range(ord('a'), ord('z') + 1):
char = chr(i)
next_node = cur_node.child.get(char)
if next_node:
display_contacts_util(next_node, prefix + char)
Display suggestions after every character enter by
the user for a given query string 'str'
def displayContacts(string): prev_node = root prefix = ""
# Display the contact List for string formed
# after entering every character
for i, char in enumerate(string):
# 'prefix' stores the string formed so far
prefix += char
# Find the Node corresponding to the last
# character of 'prefix' which is pointed by
# prevNode of the Trie
cur_node = prev_node.child.get(char)
# If nothing found, then break the loop as
# no more prefixes are going to be present.
if not cur_node:
print(f"No Results Found for {prefix}\n")
break
# If present in trie then display all
# the contacts with given prefix.
print(f"Suggestions based on {prefix} are ",end=" ")
display_contacts_util(cur_node, prefix)
print()
# Change prevNode for next prefix
prev_node = cur_node
# Once search fails for a prefix, we print
# "Not Results Found" for all remaining
# characters of current query string "str".
for char in string[i+1:]:
prefix += char
print(f"No Results Found for {prefix}\n")Insert all the Contacts into the Trie
def insertIntoTrie(contacts): # Insert each contact into the trie for contact in contacts: insert(contact)
Driver program to test above functions
Contact list of the User
contacts=["gforgeeks","geeksquiz"]
Size of the Contact List
n=len(contacts)
Insert all the Contacts into Trie
insertIntoTrie(contacts) query = "gekk"
Note that the user will enter 'g' then 'e', so
first display all the strings with prefix as 'g'
and then all the strings with prefix as 'ge'
displayContacts(query)
This code is contributed by Aman Kumar
C#
// C# Program to Implement a Phone // Directory Using Trie Data Structure using System; using System.Collections.Generic;
class TrieNode { // Each Trie Node contains a Map 'child' // where each alphabet points to a Trie // Node. public Dictionary<char, TrieNode> child;
// 'isLast' is true if the node represents
// end of a contact
public bool isLast;
// Default Constructor
public TrieNode()
{
child = new Dictionary<char, TrieNode>();
// Initialize all the Trie nodes with NULL
for (char i = 'a'; i <= 'z'; i++)
child.Add(i, null);
isLast = false;
} }
class Trie { public TrieNode root;
// Insert all the Contacts into the Trie
public void insertIntoTrie(String []contacts)
{
root = new TrieNode();
int n = contacts.Length;
for (int i = 0; i < n; i++)
{
insert(contacts[i]);
}
}
// Insert a Contact into the Trie
public void insert(String s)
{
int len = s.Length;
// 'itr' is used to iterate the Trie Nodes
TrieNode itr = root;
for (int i = 0; i < len; i++)
{
// Check if the s[i] is already present in
// Trie
TrieNode nextNode = itr.child[s[i]];
if (nextNode == null)
{
// If not found then create a new TrieNode
nextNode = new TrieNode();
// Insert into the Dictionary
if(itr.child.ContainsKey(s[i]))
itr.child[s[i]] = nextNode;
else
itr.child.Add(s[i], nextNode);
}
// Move the iterator('itr') ,to point to next
// Trie Node
itr = nextNode;
// If its the last character of the string 's'
// then mark 'isLast' as true
if (i == len - 1)
itr.isLast = true;
}
}
// This function simply displays all dictionary words
// going through current node. String 'prefix'
// represents string corresponding to the path from
// root to curNode.
public void displayContactsUtil(TrieNode curNode,
String prefix)
{
// Check if the string 'prefix' ends at this Node
// If yes then display the string found so far
if (curNode.isLast)
Console.WriteLine(prefix);
// Find all the adjacent Nodes to the current
// Node and then call the function recursively
// This is similar to performing DFS on a graph
for (char i = 'a'; i <= 'z'; i++)
{
TrieNode nextNode = curNode.child[i];
if (nextNode != null)
{
displayContactsUtil(nextNode, prefix + i);
}
}
}
// Display suggestions after every character enter by
// the user for a given string 'str'
public void displayContacts(String str)
{
TrieNode prevNode = root;
// 'flag' denotes whether the string entered
// so far is present in the Contact List
String prefix = "";
int len = str.Length;
// Display the contact List for string formed
// after entering every character
int i;
for (i = 0; i < len; i++)
{
// 'str' stores the string entered so far
prefix += str[i];
// Get the last character entered
char lastChar = prefix[i];
// Find the Node corresponding to the last
// character of 'str' which is pointed by
// prevNode of the Trie
TrieNode curNode = prevNode.child[lastChar];
// If nothing found, then break the loop as
// no more prefixes are going to be present.
if (curNode == null)
{
Console.WriteLine("\nNo Results Found for "
+ prefix);
i++;
break;
}
// If present in trie then display all
// the contacts with given prefix.
Console.WriteLine("\nSuggestions based on "
+ prefix + " are ");
displayContactsUtil(curNode, prefix);
// Change prevNode for next prefix
prevNode = curNode;
}
for ( ; i < len; i++)
{
prefix += str[i];
Console.WriteLine("\nNo Results Found for "
+ prefix);
}
} }
// Driver code public class GFG { public static void Main(String []args) { Trie trie = new Trie();
String []contacts = {"gforgeeks", "geeksquiz"};
trie.insertIntoTrie(contacts);
String query = "gekk";
// Note that the user will enter 'g' then 'e' so
// first display all the strings with prefix as 'g'
// and then all the strings with prefix as 'ge'
trie.displayContacts(query);
} }
// This code is contributed by PrinciRaj1992
` JavaScript ``
``
Output
Suggestions based on gare geeksquiz gforgeeks
Suggestions based on geare geeksquiz
No Results Found for gek
No Results Found for gekk
Time Complexity: O(n*m) where n is the number of contacts and m is the maximum length of a contact string.
Auxiliary Space: O(n*m)