Print the pattern by using one loop | Set 2 (Using Continue Statement) (original) (raw)

Last Updated : 23 Jul, 2025

Given a number n, print triangular pattern. We are allowed to use only one loop.
Example:

Input: 7 Output: *

We use single for-loop and in the loop we maintain two variables for line count and current star count. If current star count is less than current line count, we print a star and continue. Else we print a new line and increment line count.

C++ `

// C++ program to print a pattern using single // loop and continue statement #include<bits/stdc++.h> using namespace std;

// printPattern function to print pattern void printPattern(int n) { // Variable initialization int line_no = 1; // Line count

// Loop to print desired pattern
int curr_star = 0;
for (int line_no = 1; line_no <= n; )
{
    // If current star count is less than
    // current line number
    if (curr_star < line_no)
    {
       cout << "* ";
       curr_star++;
       continue;
    }

    // Else time to print a new line
    if (curr_star == line_no)
    {
       cout << "\n";
       line_no++;
       curr_star = 0;
    }
}

}

// Driver code int main() { printPattern(7); return 0; }

Java

// Java program to print a pattern using single // loop and continue statement import java.io.*;

class GFG {

// printPattern function to print pattern
static void printPattern(int n)
{
    // Variable initialization
    // Line count
    int line_no = 1; 

    // Loop to print desired pattern
    int curr_star = 0;
    for ( line_no = 1; line_no <= n;)
    {
        // If current star count is less than
        // current line number
        if (curr_star < line_no)
        {
            System.out.print ( "* ");
            curr_star++;
            continue;
        }

        // Else time to print a new line
        if (curr_star == line_no)
        {
            System.out.println ("");
            line_no++;
            curr_star = 0;
        }
    }
}

// Driver code
public static void main (String[] args)
{
        printPattern(7);
}

}

// This code is contributed by vt_m

Python 3

Python 3 program to print

a pattern using single

loop and continue statement

printPattern function

to print pattern

def printPattern(n):

# Variable initialization
line_no = 1 # Line count

# Loop to print 
# desired pattern
curr_star = 0
line_no = 1
while(line_no <= n ):

    # If current star count 
    # is less than current 
    # line number
    if (curr_star < line_no):
        print("* ", end = "")
        curr_star += 1
        continue
    
    # Else time to print
    # a new line
    if (curr_star == line_no):
        print("")
        line_no += 1
        curr_star = 0
    

Driver code

printPattern(7)

This code is contributed

by Smitha

C#

// C# program to print a pattern using single // loop and continue statement using System;

class GFG {

// printPattern function to print pattern
static void printPattern(int n)
{
    // Variable initialization
    // Line count
    int line_no = 1; 

    // Loop to print desired pattern
    int curr_star = 0;
    for ( line_no = 1; line_no <= n;)
    {
        // If current star count is less than
        // current line number
        if (curr_star < line_no)
        {
            Console.Write ( "* ");
            curr_star++;
            continue;
        }

        // Else time to print a new line
        if (curr_star == line_no)
        {
            Console.WriteLine ();
            line_no++;
            curr_star = 0;
        }
    }
}

// Driver code
public static void Main ()
{
        printPattern(7);
}

}

// This code is contributed by vt_m

PHP

JavaScript

`

Output:

Time Complexity: O(n2)
Auxiliary Space: O(1)
Please refer below post for one more approach.
Print pattern using only one loop