Conversion of Block Diagrams into Signal Flow Graphs (original) (raw)

Last Updated : 9 Mar, 2026

Conversion of block diagrams into a signal flow representation simplifies analysis of control systems. Graphical representation shows relationships between system variables using nodes and directed branches. Such representation helps engineers study signal paths and system behaviour more clearly.

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Signal Flow Graphs

Construction of Signal Flow Graph from Linear Equation

Let us consider a system which is described by a set of linear equations

x_2=a_{12}x_1+a_{12}x_3+a_{12}x_4\newline x_3=a_{23}x_2\newline x_4=a_{24}x_2+a_{32}x_3+a_{44}x_4\newline x_5=a_{25}x_2+a_{45}x_4

Where the input node is x1 and output node is x5

Now constructing the SFG

Step 1: First placing the nodes.

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Step 1

Step 2: Graph from 1st Equation

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Step 2

Step 3: Graph from 1st and 2nd equation

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Step 3

Step 4: Graph from 1st, 2nd and 3rd equation

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Step 4

Step 5: Combing all the four equations we get the final signal flow graph

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Step 5

Block Diagram

A system consists of number of components. The function of each component is represented by a block. All the blocks are interconnected by the lines with arrows indicating the flow of signal from output of onw block to another. These block diagram gives the idea of the system and the interrelation of various components of the system.

Different parts of Block Diagram

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Block Diagram

Steps to Draw Signal Flow Graph from Block Diagram

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Block Diagram to SFG conversion

Mason's Gain Formula

Mason's gain formula is used to find the overall transmittance or gain of the system from signal flow graph.

T=\frac{\Sigma_{k=1}^kP_k\Delta_k }{\Delta}

Where,

Solved Example

**Convert the block diagram into signal flow graph and find the overall transfer function

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Question Block Diagram

The signal flow diagram of the given block diagram is

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Solution

The forward paths are

P_1=G_1G_3G_4 \:\:\:\:\:P_2=-G_1G_2

The loop gains are

L_1=G_3G_4(-1)\newline L_2=G_1G_3H_1(-1)\newline L_3=G_1G_3H_1(-1)\newline L_4=G_1(-G_2)(-1)G_3H_1(-1)\newline L_5=G_1(-G_2)(-1)G_3H_1(-1)

As we can see that all loops are touching path P_1\:and \:P_2 . therefore the path factors will be unity.

\Delta=1-(L_1+L_2+L_3+L_4+L_5)\newline= 1+G_3G_4+2G_1G_3H_1+2G_1G_2G_3H_1

using mason's gain formula we get,

\frac{C}{R}=\frac{P_1\Delta_1+P_2\Delta_2}{\Delta}=\frac{G_1G_3G_4-G_1G_2}{1+G_3G_4+2G_1G_3H_1+2G_1G_2G_3H_1}

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