Defer Keyword in Golang (original) (raw)

Last Updated : 12 Jul, 2025

In Go language, defer statements delay the execution of the function or method or an anonymous method until the nearby functions returns. In other words, defer function or method call arguments evaluate instantly, but they don't execute until the nearby functions returns. You can create a deferred method, or function, or anonymous function by using the defer keyword.

Syntax:

// Function defer func func_name(parameter_list Type)return_type{ // Code }

// Method defer func (receiver Type) method_name(parameter_list){ // Code }

defer func (parameter_list)(return_type){ // code }()

Important Points:

Let us discuss this concept with the help of an example:

Example 1:

Go `

// Go program to illustrate the // concept of the defer statement package main

import "fmt"

// Functions func mul(a1, a2 int) int {

res := a1 * a2
fmt.Println("Result: ", res)
return 0

}

func show() { fmt.Println("Hello!, GeeksforGeeks") }

// Main function func main() {

// Calling mul() function
// Here mul function behaves
// like a normal function
mul(23, 45)

// Calling mul()function
// Using defer keyword
// Here the mul() function
// is defer function
defer mul(23, 56)

// Calling show() function
show()

}

`

Output:

Result: 1035 Hello!, GeeksforGeeks Result: 1288

Explanation: In the above example we have two functions named mul() and show(). Where show() function is called normally in the main() function, mul() function is called in two different ways:

Example 2:

Go `

// Go program to illustrate // multiple defer statements, to illustrate LIFO policy package main

import "fmt"

// Functions func add(a1, a2 int) int { res := a1 + a2 fmt.Println("Result: ", res) return 0 }

// Main function func main() {

fmt.Println("Start")

// Multiple defer statements
// Executes in LIFO order
defer fmt.Println("End")
defer add(34, 56)
defer add(10, 10)

}

`

Output:

Start Result: 20 Result: 90 End