Iterate Over a List of Lists in Python (original) (raw)

Last Updated : 22 Apr, 2025

We are given a list that contains multiple sublists, and our task is to iterate over each of these sublists and access their elements. **For example, if we have a list like this: [[1, 2], [3, 4], [5, 6]], then we need to loop through each sublist and access elements like 1, 2, 3, and so on.

Using Nested For Loops

This is the most straightforward way to iterate through each sublist and access individual items.

Python `

a = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

for i in a: for j in i: print(j, end=' ') print()

`

**Explanation:

Using List Comprehension

If our goal is to flatten a nested list into a single list, list comprehension offers a concise solution.

Python `

a = [[1, 2], [3, 4], [5, 6]] b = [i for sub in n for i in sub]

print(b)

`

**Explanation:

Using enumerate() on Nested Lists

We can use **enumerate() to track indices while iterating, which is helpful when we want to know the position of each sublist.

Python `

a = [['Python', 'Java'], ['C++', 'C#'], ['Go', 'Rust']]

for i, g in enumerate(a, start=1): print(f"Group {i}: {g}")

`

Output

Group 1: ['Python', 'Java'] Group 2: ['C++', 'C#'] Group 3: ['Go', 'Rust']

**Explanation:

**itertools.chain() lets us combine multiple iterables into one. It's great for flattening nested lists efficiently, especially with large datasets, as it avoids creating extra lists in memory.

Python `

from itertools import chain

a = [[1, 2], [3, 4], [5, 6]] b = list(chain(*a))

print(b)

`

**Explanation:

Also read: **matrices, **list-comprehension, **itertools.chain(), **enumerate().

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