Java Integer compareTo() method (original) (raw)

Last Updated : 03 Apr, 2023

The compareTo() method of Integer class of java.lang package compares two Integer objects numerically and returns the value 0 if this Integer is equal to the argument Integer; a value less than 0 if this Integer is numerically less than the argument Integer; and a value greater than 0 if this Integer is numerically greater than the argument Integer (signed comparison).

Syntax :

public int compareTo(Integer anotherInt) Parameter : anotherInt- : the Integer to be compared. Return :

Example 01 : To show working of java.lang.Integer.compareTo() method.

java `

// Java program to demonstrate working // of java.lang.Integer.compareTo() method import java.lang.Integer;

class Gfg {

// driver code
public static void main(String args[])
{
    Integer a = new Integer(10);
    Integer b = new Integer(20);

    // as 10 less than 20, Output will be a value less than zero
    System.out.println(a.compareTo(b));

    Integer x = new Integer(30);
    Integer y = new Integer(30);

    // as 30 equals 30, Output will be zero
    System.out.println(x.compareTo(y));

    Integer w = new Integer(15);
    Integer z = new Integer(8);

    // as 15 is greater than 8, Output will be a value greater than zero
    System.out.println(w.compareTo(z));
}

}

`

Output:

-1 0 1

**Example 02 :**The working of compareTo() method in Java to compare two integer values.

Java `

import java.io.*;

class GFG { public static void main(String[] args) { Integer num1 = 10; Integer num2 = 5; Integer num3 = 10; int result1 = num1.compareTo(num2); int result2 = num1.compareTo(num3); int result3 = num2.compareTo(num3); System.out.println("Comparing num1 and num2: " + result1); System.out.println("Comparing num1 and num3: " + result2); System.out.println("Comparing num2 and num3: " + result3); } }

`

Output :

Comparing num1 and num2: 1 Comparing num1 and num3: 0 Comparing num2 and num3: -1