BigInteger flipBit() Method in Java (original) (raw)

Last Updated : 11 Jul, 2025

Prerequisite: BigInteger Basics
The java.math.BigInteger.flipBit(index) method returns a BigInteger which is used to flip a particular bit position in a BigInteger. This method Computes (bigInteger ^ (1<<n)). The bit at index n of binary representation of the bigInteger will be flipped. That is, if the bit position is 0 it will be converted to 1 and vice versa.
Syntax:

public BigInteger flipBit(int index)

**Parameter:**The method accepts one parameter index of integer type and refers to the position of the bit to be flipped.
Return Value: The method returns the bigInteger after flipping its bit at position index.
Throws: The method throws an ArithmeticException when the value of index is negative.
Examples:

Input: value = 2300 , index = 1 Output: 2302 Explanation: Binary Representation of 2300 = 100011111100 bit at index 1 is 0 so flip the bit at index 1 and it becomes 1. Now Binary Representation becomes 100011111110 and Decimal equivalent of 100011111110 is 2302

Input: value = 5482549 , index = 5 Output: 5482517

Below program illustrate flipBit(index) method of BigInteger.

Java `

/* *Program Demonstrate flipBit() method of BigInteger / import java.math.;

public class GFG {

public static void main(String[] args)
{
    // Creating  BigInteger object
    BigInteger biginteger = new BigInteger("5482549");

    // Creating an int i for index
    int i = 5;

    // Call flipBit() method on bigInteger at index i
    // store the return BigInteger
    BigInteger changedvalue = biginteger.flipBit(i);

    String result = "After applying flipBit at index " + i +
    " of " + biginteger+ " New Value is " + changedvalue;

    // Print result
    System.out.println(result);
}

}

`

Output:

After applying flipBit at index 5 of 5482549 New Value is 5482517

Reference:https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#clearBit(int)