Arithmetic Series (original) (raw)

Last Updated : 23 Jul, 2025

An **arithmetic series is the sum of the terms of an **arithmetic sequence, where an arithmetic sequence is a sequence of numbers in which the difference between consecutive terms is constant.

Or we can say that an arithmetic progression can be defined as a sequence of numbers in which for every pair of consecutive terms, the second number is found by adding a constant number to the previous one.

Some examples includes:

**Note: If a, a + d, a + 2d, a + 3d, . . . is arithmetic sequence then a + (a + d) + (a + 2d) + (a + 3d) + . . . is arithmetic series.

There are two major formulas related to the terms of Arithmetic Series:

nth term of Arithmetic Series

The formula for nth term is,

**a n **= a + (n−1)d

where,

Sum of First n Terms

The sum of first “n” terms of the series can be easily found is we know the first term of the series and total terms. The formula for finding the sum of first "n" terms is:

**S n **= n/2 [2a + (n−1)d]

where,

**Note: The terms of an arithmetic sequence look like this: a, a + d, a + 2d, a + 3d, . . . , a + (n − 1)d

The sum of the first n terms of this sequence, Sn​, can be written as:

Sn = a + (a + d) + (a + 2d) + (a + 3d) + . . . +[a + (n − 1)d]

⇒ Sn = [a+(n−1)d] + [a+(n−2)d] + . . . + a

Now, add these two expressions for Sn​ term by term:

2Sn = (a+[a+(n−1)d]) + ((a+d)+[a+(n−2)d]) + . . . + ([a+(n−1)d]+a)

Each pair of terms in parentheses sums to the same value i.e., a+[a+(n−1)d] = 2a+(n−1)d

Thus, 2Sn = n ⋅ [2a + (n − 1)d]

**S n **= (n/2) ⋅ [2a + (n − 1)d]

Sigma Notation for Arithmetic Series

Using sigma notation, the sum of the first n terms of an arithmetic series can be expressed as:

S_n = \sum_{k=0}^{n-1} (a + kd)

Where,

**For Example: Σ 10 n=1 (3n+7)

Here the value of n starts with ‘1’ and ends at ’10’. When we start putting the value of n we get the arithmetic series just like below:

Recursive Formula

Recursive Formula gives to two information:

Suppose, we have the series 3, 5, 7..... then here the first term of the series is a1 = 3 Now, from above the series we see that the formula for an Will be as below:

If a1 = 3 than an = a(n-1) + 2

Therefore, we have to add '2' to the previous term to get to next term of the series. Hence, finding the rest of the term below:

Applications of Arithmetic Series

Arithmetic series have many practical applications across different fields, as they involve the sum of terms that increase or decrease by a constant amount. Here are some common applications:

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