Class 8 NCERT Solutions Chapter 9 Algebraic Expressions and Identities Exercise 9.2 (original) (raw)

Last Updated : 7 Aug, 2024

Question 1. Find the product of the following pairs of monomials.

**Monomial: Expression containing only one term

****(i) 4, 7p**

**Ans:

(4) * (7p) = 28p

(ii) -4p, 7p

**Ans:

(-4p) * (7p) = -28p2

**Explanation: When a negative number is multiplied to a positive number the product becomes negative.

****(iii) -4p, 7pq**

**Ans:

(-4p) * (7pq) = -28p2q

****(iv) 4p** 3 , -3p

**Ans:

(4p3) * (-3p) = -12p4

****(v) 4p, 0**

**Ans:

(4p) * (0) = 0

**Explanation: Any number when multiplied to zero (0) gives zero.

**Question 2. Find the areas of rectangles with the following pairs of monomials as their lengths and breadths respectively.

(p, q); (10m, 5n); (20x 2 , 5y 2 ); (4x, 3x 2 ); (3mn, 4np)

**Note: Area of rectangle is the product of length and breadth [length * breadth]

**Ans:

**For (p,q):

p * q = pq

For (10m, 5n):

10m * 5n = 50mn

For (20x 2 ,5y 2 ):

20x2 * 5y2 = 100x2y2

**For (4x,3x 2 ):

4x * 3x2 = 12x3

**For (3mn, 4np):

3mn * 4np = 12mn2p

**Question 3. Complete the table of products.

**Ans:

**First monomial **Second monomial 2x -5y 3x2 -4xy 7x2y -9x2y2
2x 4x2 -10xy 6x3 -8x2y 14x3y -18x3y2
-5y -10xy 25y2 -15x2y 20xy2 -35x2y2 45x2y3
3x2 6x3 -15x2y 9x4 -12x3y 21x4y -27x4y2
-4xy -8x2y 20xy2 -12x3y 16x2y2 -28x3y2 36x3y3
7x2y 14x3y -35x2y2 21x4y -28x3y2 49x4y2 -63x4y3
-9x2y2 -18x3y2 45x2y3 -27x4y2 36x3y3 63x4y3 81x4y4

**Question 4. Obtain the volume of rectangular boxes with the following length, breadth, and height respectively.

**Note: The volume of the rectangle is the product of length, breadth, height [length * breadth * height]

****(i)** **5a, 3a 2 , 7a 4

**Ans:

5a * 3a2 * 7a4 = 105a7

****(ii) 2p , 4q , 8r**

**Ans:

2p * 4q * 8r = 64pqr

****(iii) xy, 2x** 2 y, 2xy 2

**Ans:

xy * 2x2y * 2xy2 = 4x4y4

****(iv) a, 2b, 3c**

**Ans: a * 2b * 3c = 6abc

**Question 5. Obtain the product of

****(i) xy, yz, zx**

**Ans:

xy * yz * zx = x2y2z2

****(ii) a, -a** 2 , a 3

**Ans:

a * -a2 * a3 = -a6

****(iii) 2, 4y, 8y** 2 , 16y 3

**Ans:

2 * 4y * 8y2 * 16y3 = 1024y6

****(iv) a, 2b, 3c, 6abc**

**Ans:

a * 2b * 3c * 6abc = 36a2b2c2

****(v) m, -mn, mnp**

**Ans:

m * -mn * mnp = -m3n2p

Summary

Chapter 9, Exercise 9.2 of NCERT Class 8 Mathematics focuses on the addition and subtraction of algebraic expressions. This exercise teaches students how to combine like terms, simplify expressions by removing brackets, and perform basic operations with algebraic expressions. Students learn to apply the distributive property and identify terms that can be combined. This skill is fundamental for solving more complex algebraic problems and equations in higher mathematics.