Class 9 RD Sharma Solutions Chapter 25 Probability Exercise 25.1 | Set 2 (original) (raw)
Last Updated : 24 Sep, 2024
Chapter 25 of RD Sharma's Class 9 mathematics textbook delves into the fundamental concepts of probability, a crucial branch of mathematics that quantifies the likelihood of events occurring. Exercise 25.1 Set 2 focuses on applying basic probability principles to solve real-world problems, helping students develop a strong foundation in this essential topic.
What is Probability?
Probability is a measure of the likelihood that an event will occur, expressed as a number between 0 and 1. A probability of 0 indicates impossibility, while 1 represents certainty. It's calculated by dividing the number of favorable outcomes by the total number of possible outcomes, assuming all outcomes are equally likely.
Question 11. Given below is the frequency distribution table regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days.
| Conc. of SO2 | 0.00-0.04 | 0.04-0.08 | 0.08-0.12 | 0.12-0.16 | 0.16-0.20 | 0.20-0.24 |
|---|---|---|---|---|---|---|
| No of days | 4 | 8 | 9 | 2 | 4 | 3 |
Find the probability of concentration of sulphur dioxide in the interval 0.12-0.16 on any of these days.
**Solution:
Total number of days = 30
Probability of concentration of SO2 in the internal 0.12 - 0.16 =
= Favorable Outcome / Total outcome
= 2/30 = 0.06
Question 12. An organization selected 2400 families at random and surveyed them to determine a relationship between income level and the number of vehicles in a family. The information gathered is listed in the table below:
Vehicles per family
| Monthly Income(in Rs) | 0 | 1 | 2 | Above 2 |
|---|---|---|---|---|
| Less than 7000 | 10 | 160 | 25 | 0 |
| 7000-10000 | 0 | 305 | 27 | 2 |
| 10000-13000 | 1 | 535 | 29 | 1 |
| 13000-16000 | 2 | 469 | 59 | 25 |
| 16000 or more | 1 | 579 | 82 | 88 |
Suppose a family is chosen, find the probability that the family chosen is
(i) earning Rs 10000 − 13000 per month and owning exactly 2 vehicles.
(ii) earning Rs 16000 or more per month and owning exactly 1 vehicle.
(iii) earning less than Rs 7000 per month and does not own any vehicle.
(iv) earning Rs 13000 − 16000 per month and owning more than 2 vehicles.
(v) owning not more than 1 vehicle.
(vi) owning at least one vehicle.
**Solution:
Total numbers of families selected by the organization to Survey= 2400. -(According to Question)
****(i)** Let E1 be the event of selecting of family earning ₹(10000 -13000)
per month and owning exactly two vehicles.
Numbers of families earning ₹10000 –13000
per month and owning exactly 2 vehicles = 29
Required probability P(E1) = 29/2400
****(ii)** Let E2 be the event of selecting of family earning ₹16000 or
more per month and owning exactly 1 vehicle.
Number of families earning ₹16000 or
more per month and owning exactly 1 vehicle = 579
Required probability,P(E2) = 579/2400
****(iii)** Let E3 be the event of selecting of family earning than ₹ 7000 per month and
doesn't own any vehicle.
Number of families earning but ₹7000 per month and
doesn't own any vehicle = 10
Required probability, P(E3)= 10/2400 = 1/240
****(iv)** Let E4 be the event of selecting a family earning ₹(13000 -16000) per month and
owning quite 2 vehicles.
Number of families earning ₹13000-16000 per month and
owning quite 2 vehicles = 25
Required probability, P(E4) = 25/2400 = 1/96
****(v)** Let E5 be the event of selecting a family owning less than 1 vehicle.
Number of families owning less than 1 vehicle i.e. the number
of families owning 0 vehicle and 1 vehicle = 10+160+0+305+1+535+2+469+1+579 = 2069
Required probability, P(E5) = 2062/2400 = 1031/1200
****(vi)** Let P(E6) is the probability that the family of owning atleast one vehicle
P(E6) = (160+305+535+469+579+25+27+29+29+82+0+2+1+25+88)/2400
= 2356/2400 = 589/600
Question 13. The following table gives the lifetimes of 400 neon lamps :
| Lifetime | 300-400 | 400-500 | 500-600 | 600-700 | 700-800 | 800-900 | 900-1000 |
|---|---|---|---|---|---|---|---|
| Number of lambs | 14 | 56 | 60 | 86 | 74 | 62 | 48 |
A bulb is selected in random. Find the probability that the lifetime of the selected bulb is
(i) less than 400?
(ii) Between 300 to 800?
(iii) At least 700hours?
**Solution:
****(i)** The probability that the lifetime of the selected bulb is less than 400
= Favorable outcomes / Total outcome
= 14/400 = 7/400
****(ii)** The probability that the lifetime of the selected bulb is between 300 – 800 hours
= Favorable outcomes / Total outcome
= (14 +56 +60 +86 +74) / 400
= 29/40
****(iii)** The probability that the lifetime of the selected bulb is at least 700 hours
= Favorable outcomes / Total outcome
= (74 +62+ 48)/400 = 23/50
Question 14. Given below is the frequency distribution of wages (in Rs) of 30 workers in a certain factory:
| Wages(in Rs) | 110-130 | 130-150 | 150-170 | 170-190 | 190-210 | 210-230 | 230-250 |
|---|---|---|---|---|---|---|---|
| No. of workers | 3 | 4 | 5 | 6 | 5 | 4 | 3 |
A worker is selected at random. Find the probability that
(i) Less than Rs150
(ii) Atleast Rs210
(iii)More than or equal to Rs150 but less than Rs210.
**Solution:
****(i)** The probability that his wages are less than Rs 150 =
= Favorable outcomes / Total outcome
=(3 + 4) / 30 = 7 / 30
****(ii)**The probability that his wages are at least Rs 210
= Favorable outcomes / Total outcome
= (3 + 4) / 30 = 7 / 30
****(iii)** The probability that his wages are more than or equal to 150 but less than Rs 200
= Favorable outcomes / Total outcome
= (5 + 6 + 5) / 30 = 16 / 30 = 8 / 15
Summary
Exercise 25.1 Set 2 in Chapter 25 of RD Sharma's Class 9 textbook provides students with a comprehensive set of problems to practice and reinforce their understanding of basic probability concepts. Through these exercises, students learn to calculate probabilities in various scenarios, apply the fundamental principles of probability theory, and develop problem-solving skills essential for more advanced mathematical concepts.