Remainder When Dividing by 6 (original) (raw)

Last Updated : 23 Jul, 2025

We can use modular arithmetic to find the remainder when any number is divisible by 6.

To determine if a number is divisible by 6 using modular arithmetic, first break the number into its individual digits based on place value. Then, calculate the powers of 10 modulo 6 for each digit’s place value. For example, 100 (mod 6) = 1, 101 (mod 6) = 4, 102 (mod 6) = 4 and so on.

In modulo 6, the powers of 10 is always equivalent to 4 except 100 which is equivalent to 1. This can be seen in the following table:

10n (mod 6)
100 1
101 4
102 4
103 4
104 4
105 4
106 4
107 4

**Note: When dividing by 6, the remainder can only be 0, 1, 2, 3, 4, or 5.

Steps to Find Remainder When Dividing by 6

We can use following simple steps for any number to find the remainder when divided by 6.

**Step 1: Break down the number into its digits and powers of 10.

**Step 2: Calculate the modulo for each term and simplify.

Example for Finding Remainder When Dividing by 6

To check if 8274736 is divisible by 6 using modular arithmetic, we need to calculate 8274736 (mod 6). If the result is 0, then the number is divisible by 6.

Step 1: Break the number down

We can express 8274736 in terms of its digits and powers of 10:

8274736 = 8 × 106 + 2 × 105 + 7 × 104 + 4 × 103 + 7 × 102 + 3 × 101 + 6 × 100

Step 2: Calculate the sum modulo 7

Now, we calculate the sum using the modular values of the powers of 10.

**Step 3: Calculate 130 (mod 6)

Now, divide 130 by 6 and find the remainder:

130 ÷ 6 = 11 remainder 4

So, 130 (mod 6) ≣ 4 (mod 6)

Thus, 8274736 when divided by 6, leaves 4 as remainder.

Example: Find the remainder when 8173 is divided by 6.

Solution:

8173 = 8 × 103 + 1 × 102 + 7 × 101 + 3 × 100

⇒ 8173 (mod 6) ≣ 8 × 4 + 1 × 4 + 7 × 4 + 3 × 1 (mod 6)

⇒ 8173 (mod 6) ≣ (8 + 1 + 7) × 4 + 3 (mod 6) = 16 × 4 + 3 (mod 6) = 67 (mod 6)

⇒ 8173 (mod 6) ≣ 67 (mod 6) = 1 (mod 6) [as 67 = 6 × 11 + 1]

Thus, Remainder when 8173 is divided by 6 is 1.

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