Right Angled Triangle (original) (raw)

Last Updated : 26 Feb, 2026

A right-angle triangle is a type of triangle that has one angle measuring exactly 90 degrees (90°). It is also known as the right triangle.

In a right triangle, the two shorter sides are called the perpendicular and the base and meet at the right angle (90°), while the longest side, opposite the right angle, is called the hypotenuse.

hypotenuse

The sum of all the interior angles of the triangle is 180°, which is called the Angle Sum Property of a Triangle. So if any one angle is 90°, the sum of the other two angles is also 90°. They are used in many areas, from construction to navigation, and play a key role in trigonometry.

Properties of Right-Angled Triangle

Basic Formulas

**Right Triangle Formula: According to the Pythagorean theorem, in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

(Hypotenuse)2 = (Perpendicular)2 + (Base)2

**Perimeter of Right-Angled Triangle: The perimeter of the right triangle is equal to the sum of the sides.

AB + BC + AC = (a + b + c) units.

**Area of Right-Angled Triangle: The area of a right triangle is the space occupied by the boundaries of the triangle.

Area of a Right Triangle = (1/2 × base × height) square units.

Derivation of Right-Angled Triangle Area Formula

For any right-angle triangle, PQR right-angled at Q with hypotenuse PR.

Now if we flip the triangle over its hypotenuse, a rectangle is formed, which is named PQRS.

s

As we know, the area of a rectangle is given as the product of its length and width, i.e., area = length × breadth

Thus, the area of Rectangle PORS = b x h

Now, the area of the right-angle triangle is twice the area of the rectangle, then.

Thus,

Area of ∆PQR = 1/2 × Area of Rectangle PQRS

A = 1/2 × b × h

Hypotenuse of a Right-Angled Triangle

For a right triangle, the hypotenuse is calculated using the Pythagorean theorem. Theorem,

H = \sqrt{(P^2 + B^2)}

where,

**Also Check

Solved Examples Questions

**Example 1: Find the area of a triangle if the height and hypotenuse of a right-angled triangle are 10 cm and 11 cm, respectively.

Given:

Using Pythagoras' theorem,

(Hypotenuse)2 = (Base)2 + (Perpendicular)2

(11)2 = (Base)2 + (10)2

(Base)2 = (11)2 - (10)2 = 121 - 100

Base = √21 = 4.6 cm

Area of the Triangle = (1/2) × b × h

Area = (1/2) × 4.6 × 10

Area = 23 cm2

**Example 2: Find out the area of a right-angled triangle whose perimeter is 30 units, height is 8 units, and hypotenuse is 12 units.

Perimeter = base + hypotenuse + height

30 units = 12 + 8 + base

Base = 30 - 20 = 10 units

Area of Triangle = 1/2×b×h = 1/2 ×10 × 8 = 40 sq units

**Example 3: If two sides of a triangle are given, find out the third side, i.e., if the base = 3 cm and the perpendicular = 4 cm, find out the hypotenuse.

Given:

Using Pythagoras theorem,

(Hypotenuse)2 = (Perpendicular)2 + (Base)2

= 42 + 32 = 16 + 9 = 25 cm2

Hypotenuse = √(25)

Hypotenuse = 5 cm