Solving Linear Systems with Addition or Subtraction (original) (raw)

Last Updated : 23 Jul, 2025

Linear systems of equations consist of two or more equations having the same set of variables. When we put the same value of variables in every equation it must satisfy every equation. The linear equation is represented in the form (a1x + b1y = c), where x and y are variables and a, b, and c are constants. Mathematical fundamentals and linear systems of equations are widely used in many fields, including engineering, physics, computer science, economics, and more. Finding the values of the variables that concurrently satisfy each of the provided equations is the first step in solving these systems.

This article will teach us how to solve linear systems with addition or subtraction.

Table of Content

What is a Linear Systems Equation?

A linear system of equations consists of two or more equations with two or more variables. The general form of a linear system with two equations and two variables x and y can be written as:

**a 1 x + b 1 y = c 1

**a 2 x + b 2 y = c 2

where,

We have to find the value of variables x and y such that it must satisfy both the equations mentioned above.

Methods for Solving Linear Systems

There are numerous approaches for resolving linear systems, such as:

Elimination Method

In the elimination method, we combine the equations in a linear system to eliminate one of the variables. By adding or subtracting the equations, one variable is canceled out, now it is easier to solve the equation for the remaining variable.

Why should we use Elimination Method?

The variables have manipulable coefficients which makes it simple to eliminate one of the variables. Graphical approaches are not good for complex linear equations.

Types of Elimination Method

The addition and subtraction methods, which are frequently combined to form elimination techniques, will be discussed in this article.

Addition Method

By combining the equations in a system, the addition method helps to answer for the remaining variable by removing one of the variables. When one variable's coefficients are opposites or can be modified to be opposites, this strategy is especially helpful.

Subtraction Method

Comparable to the addition method, the subtraction approach removes a variable by subtracting one equation from another. When one variable's coefficients are the same or can be modified to be the same, this strategy is helpful.

Solving Linear Systems with Addition or Subtraction

Steps to solve linear system with addition or subtraction is:

**Example: For given Linear system:

**Solution:

Align both equations

Add both the above given equation to eliminate y

(2x + 3y) + (4x - 3y) = 8 + 2

6x = 10

x = 10/6 = 5/3

Subsitute value of x = 5/3 in any one equation to find y:

2x + 3y = 8

2(5/3) + 3y = 8

10/3 + 3y = 8

3y = 8 - 10/3

3y = 24/3 - 10/3

y = 14/9

Value of x = 5/3 and y = 14/9

Substitue the values of x and y in both equations to verify them.

Common Mistakes and How to Avoid Them

This is where students repeatedly commit numerous errors and get wrong answers, due to inaccurate solutions of Linear Systems.

Inconsistent Cases in Linear System

Real-Life Applications of Solving Linear Systems

Various application of solving linear system are:

Practice Questions on Solving Linear Systems with Addition or Subtraction

**Example 1: Solve the given system of equations:

**Solution:

First align the equations

Add the Equations to Eliminate y

(x + y) + (2x - y) = 5 + 1

3x = 6

x = 6/3 = 2

Substitute x = 2 into x + y = 5

2 + y = 5

y = 3

Solution of above equation x = 2 , y = 3

**Example 2: Solve the given system of equations

**Solution:

Multiply the second equation by 2 and the first by -1 to align the coefficients of y

-2(3x + 4y) = -2(7)

2(5x + 2y) = 2(8)

-6x - 8y = -14

10x + 4y = 16

Now add the equations

(-6x - 8y) + (10x + 4y) = -14 + 16

4x - 4y=2

Solve for x

4x = 2

x = 0.5

Substitute x = 0.5 into 3x + 4y = 7

3(0.5) + 4y = 7

1.5y + 4y = 7

y = 5.5/4

y = 1.375

Solution for above equation is x = 0.5 and y = 1.375

**Example 3: Solve the given system of equations:

**Solution:

Multiply the first equation by 2 to compare it with the second equation

4x + 6y = 12

4x + 6y = 12

Subtract the Equations​

(4x + 6y) - (4x + 6y) = 12-12

0 = 0

Equations are identical, meaning the system has infinitely many solutions.

**​Example 4: Solve the given system of equations:

**Solution:

Multiply the first equation by 2 to compare it with the second equation

4x + 6y = 6

4x + 6y = 12

Subtract the Equations​

(4x + 6y) - (4x + 6y) = 6 - 12

0 = -6

Equation are not equal which means that system has no solutions.

Conclusion

Using addition or subtraction, often known as the elimination approach, to solve linear systems is a strong strategy for decomposing large problems into simpler ones. Students may solve linear problems efficiently and use these skills in a variety of real-world circumstances by adhering to a methodical approach.

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