numpy.count() in Python (original) (raw)

Last Updated : 10 Oct, 2019

numpy.core.defchararray.count(arr, substring, start=0, end=None): Counts for the non-overlapping occurrence of sub-string in the specified range.

Parameters: arr : array-like or string to be searched. substring : substring to search for.start, end : [int, optional] Range to search in. Returns : An integer array with the number of non-overlapping occurrences of sub-string.

Code #1:

Python3 1== `

Python Program illustrating

numpy.char.count() method

import numpy as np

2D array

arr = ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']

print ("arr : ", arr)

print ("Count of 'tt'", np.char.count(arr, 'tt')) print ("Count of 'tt'", np.char.count(arr, 'tt', start = 0)) print ("Count of 'tt'", np.char.count(arr, 'tt', start = 8))

Output:

arr : ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz'] Count of 'tt' [2 2 1 0] Count of 'tt' [2 2 1 0] Count of 'tt' [1 2 1 0]

Code #2: